Bio & Anthro

p2 + 2pq + q2 = 1 ; where ‘p2’ represents the homozygous dominant genotype, ‘2pq’ represents the heterozygous genotype, and ‘q2’ represents the homozygous recessive genotype

The total number of Pago Fuagans that are carriers of the (g) allele and phenotypically normal =

14. In a flower garden, the gardener has purple and white pansies. He notices that a new pansy has sprouted. When it finally flowers, the pansy is lavender. Explain how this happened. (5 points) This would happen in a case incomplete dominance. The white pansies nor the purple ones genes dominated making a 50/50 offspring.

9. No, because each child's 2 sets of chromosomes are rearranged independently, so that there is an equal probability of all of them having the same genotype (1/2^4, or 1/16) as there is of them having all different ones

If one parent gives their offspring a purple stem allele while the other parent gives the offspring a non-purple cell allele, their offsprings stem will be purple. If there is two parents who both give their offspring non-purple stem alleles, their offspring will have a non-purple stem. This proves my point completely, because it shows all of the outcomes for an offspring. It also shows if you get two purple genes from your parents, you can only show a purple stem, same for the non-purple gene. And if you get one of each gene from your parents, then you’ll get a purple because purple is a dominant

3. a) A plant can have either tall (T) stems or short (t) stems. Two plants are crossed. One has the genotypeTt and the other has the genotype Tt. Fill in the Punnett square below for this cross. (1

Suppose the feather color of a bird is controlled by two alleles, D and d. The D allele results in dark feathers, while the d allele results in lighter feathers.

The “Brassica rapa” is a fast plant known as the field mustard. This plant is well known for its rapid growing rate, which makes it an easy breeding cycle and easy to pollinate. In giving so this makes “Brassica rapa” a great participant for testing Gregor Mendel’s theories of inheritance. The “Brassica rapa” acts like a test subject in testing cross-pollination giving the understanding to the dominant allele of colored stems. There are different colors that are visible on the stem that are above the soil; the colors vary from green to purple. P1 seed was ordered, germinated and cross-pollinated until germination of the next off spring of plants were also done. It was

Recall from the background information that purple corn kernels are dominant and yellow kernels are recessive. The second ear of corn was the result of crossing two heterozygous ears of male purple corn (Pp x Pp). This is represented by the Punnett square below. Complete the Punnett square by writing the correct letters that correspond to each number indicated in the table. (4 points)

Imagine that you are crossing two plants that are heterozygous for flower color and seed shape. The dominant and recessive alleles for these traits are:

Now you have determined some facts about the grounded allele and the trait that it causes. Given what you know, do you expect the mutant F1 flies to be homozygous or heterozygous for the allele that causes the grounded trait? According to your reasoning, if you mated two mutant F1 flies, what percentage of flies would you expect to be wild type versus mutant in the F2 progeny? Draw a Punnett square of this cross to justify your answer.

You are also provided with a heterozygous female, and a homozygous recessive male for a genetic cross. In this particular female, all the dominant alleles are on one chromosome, and the recessive counterparts are on the other homologous chromosome. Due to a chromosomal condition, in the female no recombination occurs between the M and N loci. Normal recombination occurs between the L and M loci. Diagram this cross, and show the genotypes and frequencies of all offspring expected from this cross.

Based on your results for the female offspring, predict whether color blindness is a dominant or recessive trait. Explain your reasoning.

During the experiment, we will talked about the differences between dominant and recessive genes and which one is more present in a small group of people. We also talked about the phenotype and genotypes of the traits we discussed. Phenotype being the physical characteristics of the trait and genotype being the genetic makeup of the trait (i.e. heterozygous, homozygous, dominant, recessive, etc.).

In this lab we considered Gregor Mendel theory of genetics. Mendel was a botanist and statistician. Mendel worked with garden peas to figure out their genetic pattern. The peas were also true-breed.1 The three principles that Mendel had for inheritance pattern are the principle of segregation, principle of dominance, and principle of independent assortment.2 The first principle of segregation means that the individual gets part of the trait from each parent that makes their traits.2 The second principle of dominance is that a trait may be present during the first generation, but doesn’t not mean it could be present in future generations and that the dominant allele is showed. The third principle of independent assortment is that it depends on the different units that are passed on that can decide your traits based on other traits that are given.2 This now goes into showing that variation of a gene is called an allele. This is now shown in a phenotype and genotype. A phenotype is showing he physical trait that we can see. A genotype is the showing of the genetic form that made that trait.3 Another term we used in this lab was homozygous which means you have two of the same alleles. The next term that was used is heterozygous which means that two different alleles were used. The term that was important that we used was a Punnett square. A Punnett square is way to be able to calculate the different potential outcomes of the genotypes graphically.3