. NaI + Cl H2O + n hexane ------- _____________ bownish solution with dark violet layer on top yellow solution with light violet layer yellow brownish solution 2. 2 mL of 1M BaCl2 and 2mL of 1M Na2SO4 ? Ba(NO3)2 + SO4(Cl)2 BaSO4 + NaCl No reaction
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- What is the concentration of Mn2+ in a solution with an analytical MnY2- concentration of 0.025 M at pH7? Kmny = 6.2 x 1013 a4 = 4.8 x 10-4 A 9.2 × 10-7 M B 8.4 × 10-13 M C 4.0 × 10-16 M D 2.0 × 10-8 M15. A 300.00 mL solution of 0.00165 M A2B5 is added to a 230.00 mL solution of 0.00380 M C2D3. What is pQsp for A2D5?100 mL water sample was subjected to DO analysis using the Winkler method. The initial reading of the titrant (0.025 M Na2SO3) in the buret was 2.51 mL. The endpoint was obtained and the final reading was 7.07 mL. A blank was also titrated and 0.75 mL of the titrant was consumed. Compute for the amount of DO (mg/L) in the sample.
- A procedure7 for determining halogens in organic compounds uses an argentometric titration. To 50 mL50 mL of anhydrous ether is added a carefully weighed sample (10−100 mg)(10−100 mg) of unknown, plus 2 mL2 mL of sodium dispersion and 1 mL1 mL of methanol. (Sodium dispersion is finely divided solid sodium suspended in oil. With methanol, it makes sodium methoxide, CH3O−Na+,CH3O−Na+, which attacks the organic compound, liberating halides.) Excess sodium is destroyed by slowly adding 2‑propanol, followed by 100 mL100 mL of water. (Sodium should not be treated directly with water because H2H2 can explode in the presence of O2O2: 2Na+2H2O⟶2NaOH+H2.)2Na+2H2O⟶2NaOH+H2.) This procedure gives a two‑phase mixture, with an ether layer floating on top of the aqueous layer that contains the halide salts. The aqueous layer is adjusted to pH 44 and titrated with Ag+,Ag+, using the electrodes in Figure 7‑5.How much 0.02916 M AgNO30.02916 M AgNO3 solution will be required to reach each equivalence…The Kjedahl procedure was used to analyze 256 µL of a solution containing 37.0 mg protein/mL. The liberated NH3 was collected in 5.00 mL of 0.033 6 M HCl, and the remaining acid required 6.34 mL of 0.010 M NaOH for complete titration. What is the weight percent of nitrogen in the protein? wt%EDTA: 0.2 M solution KH2PO4: 0.4 solution Sodium Nitrate MW: 84.9947 g/mol A 150 mL buffer solution of 50 mM of sodium nitrate, 25 mM KH2PO4, 0.05 mM EDTA (acid) is needed. How much of each is needed, also include how much water?
- Assuming that the standard solution contains 20.0 g/L of Red Dye #40, report the concentration in g/L of Red Dye #40 in your unknown. The path length is 1.00cm To test the unknown and standard solution, 0.1 mL of the unknown was dispensed into a 50-mL volumetric flask about three-fourths full with deionized water. this was done 1 more time for the unknown and two times for the standard solution. Therefore at the end, there were 4 flasks each with 0.1 mL of sample (2-unknown and 2-standard solution).alculate the Ksp of a Ca(OH)2 solution using the data below: Titrated with 0.103MHCl Initial syringe value: 9.71 Final Syringe value: 1.53 Volume of Ca(OH)2 titrated 24.39 mLA 10.00-mL aliquot of a known HCl solution (3.800 g/L) was titrated with a 4.100 g/L NaOH solution. Calculate the range of the blank corrected titration volumes using the titration data below: Blank Trial 1 Trial 2 Trial 3 Initial Volume (mL) 12.50 0.50 12.30 34.75 Final Volume (mL) 13.10 10.45 22.35 45.27
- Need solution to all parts if not answered I'll downvote solution Find the pH during the titration of 20.00 mL of 0.1910 M benzoic acid, C6H5COOH (Ka = 6.3 10-5), with 0.1910 M NaOH solution after the following additions of titrant. (a) 0 mL (b) 10.00 mL (c) 15.00 mL (d) 20.00 mL (e) 25.00 mLMake oleic acid vesicles by making a solution of 0.5mL of 50mM oleic acid, 1 mM HPTS in 0.2 M Tris-HCl, 50 mM NaCl, pH 8.5 (i.e. buffer A) in a microcentrifuge tube in the following order. How much HPTS should you add? How much oleic acid?You want to measure the concentration of carbonate (CO32-) in a mildly basic solution by using an EDTA back titration. CaCO3 has a Ksp of 5x10-9. You add 50.00 mL of 0.3484 M CaCl2 to 500.0ml of sample and filter the solution to remove the precipitate. You then take 250.0 mL of the filtered solution and titrate with 0.1786 M EDTA. You require 23.72 mL to reach the endpoint. What is the concentration of carbonate in the original sample?