0.5 gr of a diprotic acid is dissolved in water and titrated with 10 mL 1 M KOH to phenolphthalein end point. What is the molar mass of the acid? ½ H2A (aq) + KOH (aq) --> ½ K2A (aq) + H2O (l) Molar mass of KOH: 56 gr/mol a. 100 gr/mol b. 150 gr/mol c. 200 gr/mol d. 50 gr/mol

0.5 gr of a diprotic acid is dissolved in water and titrated with 10 mL 1 M KOH to phenolphthalein end point. What is the molar mass of the acid? ½ H2A (aq) + KOH (aq) --> ½ K2A (aq) + H2O (l) Molar mass of KOH: 56 gr/mol a. 100 gr/mol b. 150 gr/mol c. 200 gr/mol d. 50 gr/mol

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter14: Principles Of Neutralization Titrations

Section: Chapter Questions

Problem 14.32QAP

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Question

0.5 gr of a diprotic acid is dissolved in water and titrated with 10 mL 1 M KOH to phenolphthalein end point. What is the molar mass of the acid?

½ H₂A (aq) + KOH (aq) --> ½ K₂A (aq) + H₂O (l)

Molar mass of KOH: 56 gr/mol

100 gr/mol

150 gr/mol

200 gr/mol

50 gr/mol

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