1. Calculate the molar concentration of the hydrochloric acid solution if you know that sp.g (specific gravity) 1.19 and percentage of 37% is the volume requited to prepare 100ml of hydrochloric acid at concentration of 6M. 2. Calculate the molar concentration of the nitric acid if you know that specific gravity is 1.42 and the percentage is 70% to prepare. Solution has concentrated of 0.4 M in 100ml of distilled water
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- What is the molarity of a concentrated solution of sulfuric acid with a specific gravity of 1.84 and 95.0% by weight sulfuric acid? specific gravity = density of substance at certain temp/density of water at 4 degrees C the density of water is 0.999973 g/mL at 4 degrees celsius. Describe how to prepare 3.0 L of 0.100M. I will pipet ______ and add this to 200mL water. The solution will be stirred and diluted to 3L with water.Prepare 1500mL of 0.5N H2SO4 solution with specific gravity of 1.84g/mL and assay of 97%1) How many milliliters of 70% ethanol and 20% ethanol must be mixed to prepare 500ml of 30% ethanol? 2) A gaseous blend of nitric oxide and nitrogen (NOmax) contains 0.09% v/v nitric oxide (NO) and 99.92% v/v nitrogen. Express the strength of nitric oxide in PPM (round to whole number) 3) The ratio strength of a 10mL vial of neostigmine methylsulfate injection USP is 1:1500.Calculate the amount of neostigmine methylsulfate in milligrams contained in the 10mL vial. (Round to the whole number).
- Please answer fast How much crystalline sugar (10% moisture content by weight) must be added to 35 litres of 10.5° Brix apple juice (specific gravity = 1.040) in order to obtain an 39° Brix final solution ? (Express the answer in kg to one decimal place).Volume of an unknown used was 30 mL, Initial Buret volume was 0 and the Final Buret volume was 8.5 mL. What is the molarity of the unknown solution if the Net volume of NaOH being used was 8.5 mL and Millimoles (mmoles) NaOH reacted was 0.791? Then, what is the Mass (g) of Acetic Acid in unknown sample and thr average percent (%) Acetic Acid? (assume density = 1g/mL)A) A solution made by adding 1.63 g of K2S (MM=110.3 g/mol) to 10.0 mL of H2O has a volume at 20oC of 11.1 mL. Find the molarity and normality of the solution. B) Give the molar concentration of HCl with a specific gravity of 1.18 and 37.0% (w/w) purity (MM=36.5 g/mol) Kindly answer all with complete solution
- 1.) Use the line of best ! Tables: Data Port 1. Synthesis of Asprin \table[[Mass of galicylic Acid used 2.024gt to calculate the concentration of the salicylic Acid in your asprin saple solution (in 50.0 ml volumettic flask) 2.) Use M1V1 = M2V2 to determine the concentration of salicylic acid in your 100.0 mL solution before dilutuon to 50.0mL for analysis. 3.) Determine the mass of salicylic acid present in the 4g sample of synthesized asprin tht was dissolved in the 100.0ml, volumetric flask 4.) Determine the percent of salicylic acid and percent asprin in the 4g sample of synthesized asprin7 5.) Calculate the theoretical yelld of asprin for your synthesis reaction. Assume that the salicylic acid used in the salicylic used in the synthesis reaction is the limiting reactant. 6. Determine the percent yild of the asprin for your synthesis. For the 1st cacization i got 1.340x10^-4 M C7H603 For the 2nd calculation i got M167x10^-5 Please check my calculations and explain the remainingPreparation of 100 ml 1.0 molar (1.0M) H2SO4 solution (specific gravity, 1.8 g/ml and purity, 98%). H2SO4 molecular weight is 98 grams.What's the differences between two questions? Q1) How much calcium would you ingest by drinking one 8 oz glass of your tap water? Show all calculations. -->Tap water 8Oz = 8 x 0.0296L = 0.2368L Hardness = 66.73ppm = 66.73mg/L CaCO3 1L has 66.73mg CaCO3 0.2368L has 66.73mg x 0.2368 = 15.8017mg MW of CaCO3 = 100g/mol MW of Ca = 40g/mol 100g CaCO3 has 40gf of Ca 15.8017mg CaCO3 has 40/100 x 15.8017mg Ca We would ingest 6.321mg of Ca. Q2) What percentage of the recommended daily dose of calcium (1,150 mg/day) does 1.0 L of your water provide? Show all calculations. --> 66.73mg/1150mg x 100 = 5.80% My Question) Why this calculation is wrong? I think this calculation is same with question 1. Isn't it? CaCO3 = 100g/mol, Ca = 40g/mol 100g CaCO3 has 40g Ca. 66.73 CaCO3 has 40/100 x 66.73mg Ca Ca = 26.70mg 26.70mg/1150mg x 100 = 2.32%
- 4. A fat sample with combination of acids contain standard hydrochloric acid for blank and sample with 8mL and 5mL respectively. The normality of the standard hydrochloric acid is 0.93N and the weight of the sample is 3 grams. Calculate the saponification value.1. Order: isoproterenol 2 mg in 500 mL D5W to infuse at 15 mL/hrPatient weight: 20 kgHow many mcg/kg/min is the patient receiving? (Round to the 2nd decimal place/hundredth placeCalculate the gram of hydrochloric acid mixed, 25 %, specific gravity 1.19, to prepare 300 ml of a 0.2 M solution? (Gpt/Ai Answer not allowed) And should correct