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Prepare the following solutions:
100.0 mL 0.0500 M stock Ca2+ solution
50.0 mL 0.0050 M working standard Ca2+ solution from 0.0500 M Ca2+
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- Preparation of 100 ml 1.0 molar (1.0M) H2SO4 solution (specific gravity, 1.8 g/ml and purity, 98%). H2SO4 molecular weight is 98 grams.Six 50.0 ml volumetric flask 1 through 6 are labeled. 10.00 ml of 2.00 x 10-1 M Fe(NO3)3 solution was then pipet into each volumetric flask. A 1.00,2.00,3.00,4.00 and 5.00ml of 2.00 x 10-3M NaSCN solution was then pipetted to flask 2 through 6 respectively. A sufficient amount of 0.10 M nitric acid was then added to each flask to make each a total volume of 50.00ml. Hint M1V1=M2V2 a)what would be the concentration of Fe(NO3)3 in 0.10M HNO3? b)what would be the concentration of NaSCN in 0.10M HNO3?1) How many milliliters of 70% ethanol and 20% ethanol must be mixed to prepare 500ml of 30% ethanol? 2) A gaseous blend of nitric oxide and nitrogen (NOmax) contains 0.09% v/v nitric oxide (NO) and 99.92% v/v nitrogen. Express the strength of nitric oxide in PPM (round to whole number) 3) The ratio strength of a 10mL vial of neostigmine methylsulfate injection USP is 1:1500.Calculate the amount of neostigmine methylsulfate in milligrams contained in the 10mL vial. (Round to the whole number).
- Six 50.0 ml volumetric flask 1-6 are labeled. 10.00 ml of 2.00 x 101 M Fe(NO3)3 solution was then pipet into each volumetric flask. A 1.00,2.00,3.00,4.00 and 5.00ml of 2.00 x 10-3M NaSCN solution was then pipetted to flask 2 through 6 respectively. A sufficient 0.10 M nitric acid was then added to each flask to make them total volume of 50.00ml. 1.a)Calculate the final Fe(NO3)3 concentrations for each. 1.b)Also how would you find the initial concentration of SCN- for each flask? Please show calculations to solutions.ThanksPrepare 50ml of approximately 1000ppm Mn stock solution from MnCl2*4H2)Prepare 1500mL of 0.5N H2SO4 solution with specific gravity of 1.84g/mL and assay of 97%
- The solubility of suberic acid C6H12(COOH)2 is 0.14 g/100 ml H2O and 0.56g/100 ml ethyl ether at 15 0C. Calculate the weight of suberic acid removed from 50 ml aqueous solution containing 40 mg acid by extraction with 50 ml ether. Calculate the weight of acid that would be removed by two successive 25 ml extraction with ether.Percentage or Ratio Strength Concentration.Show your complete solution. 1. If 250 mL of 15% (v/v) solution of methyl salicylate in alcohol is diluted to 1500 mL, what will be the percentage strength (v/v) of the final solution? *Note: Indicate the unit. Give your answer in 2 decimal places. Example 100.00 %1. Give the molar concentration of HCl with a specific gravity of 1.18 and 37.0% (w/w) purity (MM=36.5g/mol) 2. A solution made by adding 1.63 g of K2S (MM=110.3 g/mol) to 10.0 mL of H2O has a volume at 20oC of 11.1 mL. Find the molarity and normality of the solution.
- The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? A. Solution A: 0.123 Solution B: 0.463 B. Solution A: 0.463 Solution B: 0.234 C. Solution A: 0.123 Solution B: 0.234 D. Solution A: 0.234 Solution B: 0.463The first goal is to make the oxalic acid standard solution. You measure 1.5232 g of oxalic acid on an analytical balance, add it to a 250-mL volumetric flask and add deionized H2O to a final volume of 250.0 mL. Molar mass of H2C2O4•2H2O = 126.07 g/mol Mass of H2C2O4•2H2O = 1.5232g Volume of H2C2O4•2H2O solution = 250.0mL What is the Molarity H2C2O4 standard solution ?What volume of 10 ma/m % KOH solution is needed (with a density of 1.09 g/cm3) toneutralize 25 cm3 15 m/v % acetic acid solution?MM [CH3COOH] = 60 g/molMM [KOH] = 56.1 g/mol
