4. List comprehension. a) Implement a list comprehension that creates a list of all odd numbers between 1 and 20 inclusive. b) Print the list with the elements separated by a space. Output Example 1 3 5 7 9 11 13 15 17 19 5. List slicing. a) Use a list comprehension to generate a list of all even numbers from 0 to 100 inclusive. Print the list. b) Use slicing to print the first five numbers in the list. c) Use slicing to print the last five numbers in the list. Hint: use len () d) Use slicing to print all list numbers between 25 and 30 inclusive. 2 Output Example [0, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50] [0, 2, 4, 6, 8] [32, 34, 36, 38, 40, 42, 44, 46, 48, 50] [20, 22, 24, 26, 28, 30]

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6.9 LAB: All permutations of names   Write a program that lists all ways people can line up for a photo (all permutations of a list of Strings). The program will read a list of one word names (until -1), and use a recursive method to create and output all possible orderings of those names, one ordering per line. When the input is: Julia Lucas Mia -1 then the output is (must match the below ordering): Julia Lucas Mia Julia Mia Lucas Lucas Julia Mia Lucas Mia Julia Mia Julia Lucas Mia Lucas Julia   import java.util.Scanner;import java.util.ArrayList; public class PhotoLineups { // TODO: Write method to create and output all permutations of the list of names.public static void allPermutations(ArrayList<String> permList, ArrayList<String> nameList) {} public static void main(String[] args) {Scanner scnr = new Scanner(System.in);ArrayList<String> nameList = new ArrayList<String>();ArrayList<String> permList = new ArrayList<String>();String name;//…

5.19 LAB: Adjust list by normalizing   When analyzing data sets, such as data for human heights or for human weights, a common step is to adjust the data. This can be done by normalizing to values between 0 and 1, or throwing away outliers. For this program, adjust the values by dividing all values by the largest value. The input begins with an integer indicating the number of floating-point values that follow. Assume that the list will always contain less than 20 floating-point values. For coding simplicity, follow every output value by a space, including the last one. And, output each floating-point value with two digits after the decimal point, which can be achieved as follows:printf("%0.2lf ", yourValue); Ex: If the input is: 5 30.0 50.0 10.0 100.0 65.0 the output is: 0.30 0.50 0.10 1.00 0.65 The 5 indicates that there are five floating-point values in the list, namely 30.0, 50.0, 10.0, 100.0, and 65.0. 100.0 is the largest value in the list, so each value is divided by 100.0.…

def large_rec(m: list[list[int]], r: int, c: int) -> int:"""Do not use any imports,  dictionaries, try-except statements or break and continue  please you must make use of the helper long here as you loop througheach row of the matrix returns the area of the largest rectangle whose top left corner is atposition r, c in m.>>> case1 = [[1, 0, 1, 0, 0],... [1, 0, 1, 1, 1],... [1, 1, 1, 1, 1],... [1, 0, 0, 1, 0]]>>> largest_at_position(case1, 1, 2)6""" Helper code: def long(lst: list[int]) -> int: count = 0i = 0while i < len(lst) and lst[i] != 0:i = i + 1count = count + 1return count

Please answer this ques in python with showing the code