175.0 mL of 0.2015 M nitric acid was added to 1.4213 g of impure calcium carbonate sample. The excessacid was back titrated with 72.5mL of 0.1152 M sodium hydroxide to reach the endpoint. Calculate for the percent calcium carbonate? (MM of CaCO3= 100.0869 g/mol) 2HNO3 + CaCO3 → Ca(NO3)2 + H2O + CO2 HNO3 + NaOH → NaNO3 + H2O
175.0 mL of 0.2015 M nitric acid was added to 1.4213 g of impure calcium carbonate sample. The excessacid was back titrated with 72.5mL of 0.1152 M sodium hydroxide to reach the endpoint. Calculate for the percent calcium carbonate? (MM of CaCO3= 100.0869 g/mol) 2HNO3 + CaCO3 → Ca(NO3)2 + H2O + CO2 HNO3 + NaOH → NaNO3 + H2O
Chapter16: Applications Of Neutralization Titrations
Section: Chapter Questions
Problem 16.24QAP
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175.0 mL of 0.2015 M nitric acid was added to 1.4213 g of impure calcium carbonate sample. The excessacid was back titrated with 72.5mL of 0.1152 M sodium hydroxide to reach the endpoint. Calculate for the
percent calcium carbonate? (MM of CaCO3= 100.0869 g/mol)
2HNO3 + CaCO3 → Ca(NO3)2 + H2O + CO2
HNO3 + NaOH → NaNO3 + H2O
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