1A8AH 2A3A 4A 5A 6A 7A HeBCNOF NLi Be1B 2B AI Si P S CI ArNa Mg 3B 48 58 6B 7B eK Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br KrRb Sr V 2r Nb Mo Te Ru Rh Pd Ag Ca In Sn Sb Te XeCS Ba La H Ta w Re Os Ir Pt Au Hg T Pb Bi Po At RnFr Ra Ac Rf HaCe Pr Nd Pm Sm Eu 6d Tb Dy Ho Er Im Yb LuTh Pa U Np Pu Am Cm Bk C Es Fm Md No LrAmonatomic ion with a charge of -2 has an electronic configuration of ls22s22p3s^3p6This ion is a(n)What is the chemical symbol of the noble gas this ion is isoelectronic with?What is the formula of the ion?

Given, a monoatomic ion with charge of -2 has an electron configuration of 1s2 2s2 2p6 3s2 3p6Since,…

Answered: 1A 8A H 2A 3A 4A 5A 6A 7A He BCNOF N Li…

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter2: Atoms, Molecules, And Ions

Section: Chapter Questions

Problem 85QAP

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A materials engineer has filed for a patent for a new alloy to be used in golf club heads. The composition by mass ranges from 25 to 31% manganese, 6.3 to 7.8% aluminum, 0.65 to 0.85% carbon, and 5.5 to 9.0% chromium, with the remainder being iron. What are the maximum and minimum percentages of iron possible in this alloy? Use Figure 2.12 to snake a prediction about how the density of this alloy would compare with that of iron; justify your prediction.
These questions concern the work of J. J. Thomson: From Thomson’s work, which particles do you think he would feel are most important in the formation of compounds (chemical changes) and why? Of the remaining two subatomic particles, which do you place second in importance for forming compounds and why? Come up with three models that explain Thomson’s findings and evaluate them. To be complete you should include Thomson’s findings.
F2(g)+2e-→2F-(aq) 2.866 O3(g)+2H+(aq)+2e-→O2(g)+H2O(l) 2.076 Co3+(aq)+e-→Co2+(aq) 1.92 H2O2(aq)+2H+(aq)+2e-→2H2O(l) 1.776 Ce4+(aq)+e-→Ce3+(aq) 1.72 Au+(aq)+e-→Au(s) 1.692 PbO2(s)+4H+(aq)+SO42-(aq)+2e-→PbSO4(s)+2H2O(l) 1.691 MnO4-(aq)+8H+(aq)+5e-→Mn2+(aq)+4H2O(l) 1.507 Au3+(aq)+3e-→Au(s) 1.498 Cr2O72-(aq)+14H+(aq)+6e-→2Cr3+(aq)+7H2O(l) 1.36 Cl2(g)+2e-→2Cl-(aq) 1.358 O2(g)+4H+(aq)+4e-→2H2O(l) 1.229 MnO2(s)+4H+(aq)+2e-→Mn2+(aq)+2H2O(l) 1.224 2IO3-(aq)+12H+(aq)+10e-→I2(s)+6H2O(l) 1.195 Br2(l)+2e-→2Br-(aq) 1.066 VO2+(aq)+2H+(aq)+e-→VO2+(aq)+H2O(l) 0.991 HNO2(aq)+H+(aq)+e-→NO(g)+H2O(l) 0.983 NO3-(aq)+4H+(aq)+3e-→NO(g)+2H2O(l) 0.957 2Hg2+(aq)+2e-→Hg22+(aq) 0.92 Hg2+(aq)+2e-→Hg(l) 0.851 Ag+(aq)+e-→Ag(s) 0.800 Hg22+(aq)+2e-→2Hg(l) 0.797 Fe3+(aq)+e-→Fe2+(aq) 0.771 O2(g)+2H+(aq)+2e-→H2O2(aq) 0.695 MnO4-(aq)+2H2O(l)+3e-→MnO2(s)+4OH-(aq) 0.595 I2(s)+2e-→2I-(aq) 0.536 Cu+(aq)+e-→Cu(s) 0.521 O2(g)+2H2O(l)+4e-→4OH-(aq)…
Am I right? Calculate the mass percentage of water in the hydrate. Show the calculations. Sample 1 : 60.87% Mass of hydrate : 0.46g Mas of water : 0.28g Mass percentage of water in the hydrate = 0.28g/0.46g x 100 = 60.87% Sample 1 2 3 Calculations for sample 1 Mass of aluminum dish 1.24g 1.26g 1.24g - Mass of aluminum dish + Epsom salt 1.70g 1.94g 1.80g - Epsom salt, original (hydrated) mass 0.46g 0.68g 0.56g 1.70g – 1.24g = 0.46g Mass of aluminum dish + Epsom salt after heating 1.42g 1.62g 1.61g Epsom salt, heated (dehydrated) mass 0.18g 0.36g 0.37g 1.42g- 1.24g = 0.18g Mass of water 0.28g 0.32g 0.19g 0.46g – 0.18g = 0.28g Moles of magnesium sulfate 0.0015mol 0.0030mol 0.0031mol 0.18g x (1mol/120.37g)= 0.0015mol Moles of water 0.016mol 0.018mol 0.011mol 0.28g x (1mol/18.02g) = 0.016mol Ratio of moles water: moles of magnesium sulfate 32:3 18:3 11:3.1…
Naturally occurring cobalt consists of only one isotope, 59Co , whose relative atomic mass is 58.9332. A synthetic radioactive isotope of cobalt, 60Co , relative atomic mass 59.9338, is used in radiation therapy for cancer. A 1.7320 g sample of cobalt has an apparent "atomic mass" of 58.9901. Find the mass of 60Co in this sample. Express your answer with the appropriate units. Express no of atoms using four significant figures 21.899 g Cr 46.347 gS 12.360 g Pt 96.471 g Sn
Calculate the mass of Cu in g from 8.20 kg CuFeS2
Convert atomic mass of Ca to g. atomic mass of Ca is 40.08 amu Group of answer choices A.) 3.00 x 10exp-18 g B.) 1.20 x 10exp22 g C.) 6.653 x 10 exp-23 g D.) 6.653 x10exp-22 g
There are 1.699 x 1022 atoms in 1.000 g of chlorine. Assume that chlorine atoms are spheres of radius 0.099 nm and that they are lined up side by side in a 0.50 g sample. How many miles in length is the line of chlorine atoms in the sample? 1 mi = 1609 m
Ecell Mg‎2+(aq) + 2 e- -> Mg(s) Mg2 + |M‎g = - 2.372 Sn4‎+(aq) + 2 e- -> S‎n2+(aq) Sn2 + , Sn4 + |Pt = + 0.154 Cl‎2 (g) + 2 e- -> 2 Cl-(‎aq Cl-| Cl2 |Pt = +1.‎36 Whic‎h of the follo‎wing is best reduc‎ing ag‎ent for Cl2(g)? a. Mg‎(s) b. Mg‎2+(aq c. Sn4‎+(aq) d. Sn2‎+(aq
Mass of crucible and cover 12.73g 2. Mass of crucible, cover, and sample 24.11g 3. Mass of original sample 24.11- 12.73g= 11.97g 4. Mass of crucible, cover, and sample after 1st heating 20.01g 6. Mass of crucible, cover, and sample after 2nd heating (assume that this step was done) 19.98 g 7. Total mass lost by sample during heating what is the percentage of water in the sample? and what is the total mass lost by the sample?
Suppose that mercury forms a perfect spherical droplet with a diameter of 5.0 mm. (a) What is the volume of the mercury droplet in cubic centimeters (cm3)? (b) If the density of mercury is 13.6 g/cm3, calculate the mass of the droplet. (c) How many mercury atoms are present in the droplet? (Volume of sphere = (4/3)3.14r3)
A 4.450 g sample of hydrated lithium iodide, LiI·xH2O, is dried in an oven. When the anhydrous salt is removed from the oven, its mass is 3.170 g. What is the value of x? A. 3 B. 4 C. 5 D. 2

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