1A8AH 2A3A 4A 5A 6A 7A HeLi BeBC NO F NeNa Mg 3B 4B 5B6B 7B - 8B ¬ 1B 28 A1 Si PS CI ArK Ca sc Ti v Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br KrRb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag cd In Sn Sb Te I XeCs Ba La Hf Ta w Re Os Ir Pt Au Hg TI Pb Bi Po At RnFr Ra Ac Rf HaCe Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb LuTh Pa U Np Pu Am Cm Bk Cf Es Fm Md No LrWrite the complete electron configuration for the silicon atom.Using NOBLE GAS notation write the electron configuration for the sodium atom.

1. The electron configuration of silicon atom number of electrons in Si atom= 14 In order to write…

Answered: 1A 8A H 2A 3A 4A 5A 6A 7A He Li Be BC…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter1: The Nature Of Chemistry

Section: Chapter Questions

Problem 88QRT

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A materials engineer has filed for a patent for a new alloy to be used in golf club heads. The composition by mass ranges from 25 to 31% manganese, 6.3 to 7.8% aluminum, 0.65 to 0.85% carbon, and 5.5 to 9.0% chromium, with the remainder being iron. What are the maximum and minimum percentages of iron possible in this alloy? Use Figure 2.12 to snake a prediction about how the density of this alloy would compare with that of iron; justify your prediction.
1 A)5.63,4.42,2.50,or 1.25 1 B)L,g,mol,or kg 2 A)129,0.109,86.0,or 57.5 2 B)g,mol,L,or mg
Perform the following mathematical function.51.11 + (0.97/2.414 × 0.32150 × e.-3.25) + 1.52444 3.4 The written value of 1.0 μm meansa. 102 mb. 10-2 mc. 106 m d. 10-6 m e. 10-9 m 1.2 An example of a physical property isA) the reaction of rubidium with water to form rubidium hydroxideB) the density of boronC) the burning of sulfur to form sulfur dioxideD) the reaction of cesium with oxygen to form cesium superoxideE) the energy content of liquid sodium
Palladium (Pd) is an element with properties similar to those of platinum. It is useful in eliminating harmful emission produce by internal combustion engines. Two students were given identical cylindrical “palladium” bars with the following data: Mass = 96.03 g; Length = 10.7 cm; Diameter = 9.82 mm; Density = 12.02 gcm-3 Show the calculations that Student K and S would do if: I) Student K was asked to determine whether his bar was made of pure palladium. II) Student S was asked to calculate the grams of ethyl alcohol (d = 0.789 gcm-3) his bar would displace.
A piece of copper has a volume of 560 L what is mass of sample in grams. For the problem it gives me 1cm^3Cu = 9g CU 9.5 x 10^21 atoms Cu= 1 Cu 1KG =1000g 1cm^3 =1mL 1L=1000cm^3 It basically wants me to write out the conversions correctly i just dont know which ones to use. Thank you so much for the help I really appreciate it.
a.) I=R, II = Rb.) I = S, I = Rc.) I=R, II = Sd.) I= S, I = S
A student performed an analysis of a sample for its calcium content andgot the following results: 14.92% 14.91% 14.88% 14.91%The actual amount of calcium in the .sample is 15.70%. What conclusions can you draw about the accuracy and precision of these results?
11. A stack of 500 sheets of typed paper is 1.9 inches thick. The thickness, in inches, of a stack containing a mol of sheets of this paper is: Answers: a)9.27 X 10^-23 b)5.27 X 10^-20 c)1.43 X 10^-23 d)2.3 X 10^21 e)6.02 X 10^23
Bromine (Br) and mercury (Hg) are the only two elements that occur as liquids at room temperature and pressure; the specific gravities of those liquids are 3.124 and 13.6 respectively.What is the combined mass of one 16 fl-oz. pint of mercury and one cup of bromine in lbm? 1 U.S. gallon = 4 quarts = 8 (16-fl. oz.) pints = 16 cups1 fl. oz. of water has a mass of 29.574 g
The density of Neon (Ne) at a specific temperature and pressure is 3.21 x 10-5 lb/in3. Calculate the volume of 1.2 x 108 Ne atoms, in cm3, under these conditions. 1000 lb = 453.6 g 1 inch = 2.54 cm
Am I right? Calculate the mass percentage of water in the hydrate. Show the calculations. Sample 1 : 60.87% Mass of hydrate : 0.46g Mas of water : 0.28g Mass percentage of water in the hydrate = 0.28g/0.46g x 100 = 60.87% Sample 1 2 3 Calculations for sample 1 Mass of aluminum dish 1.24g 1.26g 1.24g - Mass of aluminum dish + Epsom salt 1.70g 1.94g 1.80g - Epsom salt, original (hydrated) mass 0.46g 0.68g 0.56g 1.70g – 1.24g = 0.46g Mass of aluminum dish + Epsom salt after heating 1.42g 1.62g 1.61g Epsom salt, heated (dehydrated) mass 0.18g 0.36g 0.37g 1.42g- 1.24g = 0.18g Mass of water 0.28g 0.32g 0.19g 0.46g – 0.18g = 0.28g Moles of magnesium sulfate 0.0015mol 0.0030mol 0.0031mol 0.18g x (1mol/120.37g)= 0.0015mol Moles of water 0.016mol 0.018mol 0.011mol 0.28g x (1mol/18.02g) = 0.016mol Ratio of moles water: moles of magnesium sulfate 32:3 18:3 11:3.1…
A student performed an experiment of heating a hydrate and obtained the following data. the mass of the empty crucible was 17.556g the mass of crucible and a hydrate was 21.018g the mass of the crucible and anhydrous salt ( after heating ) was 19.641g Calcualte the mass of the hydrated salt.

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