1A 8A H 2A 3A 4A SA 6A 7A He CNOF Ne Li Be В B 2B ASi PS CI Ar Na Mg 3B 4B 5B 6B 7B г 68 K Ca Sc TiV Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Xe Rb Sr Y Zr ND MO Tc Ru Rh Pd Ag ca In Sn Sb Te Cs Ba La Hf Ta Re Os Ir Pt Au Hg TI Pb Bi Po At Rn Fr Ra Ac Rf Ha Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa UNp Pu Am Cm Bk Cf Es Md No Lr Considering only ions with charges of+1, +2, -1 and -2, or neutral atoms, give the symbols for 4 species that are isoelectronic with the chloride ion, Cl

1A 8A H 2A 3A 4A SA 6A 7A He CNOF Ne Li Be В B 2B ASi PS CI Ar Na Mg 3B 4B 5B 6B 7B г 68 K Ca Sc TiV Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Xe Rb Sr Y Zr ND MO Tc Ru Rh Pd Ag ca In Sn Sb Te Cs Ba La Hf Ta Re Os Ir Pt Au Hg TI Pb Bi Po At Rn Fr Ra Ac Rf Ha Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa UNp Pu Am Cm Bk Cf Es Md No Lr Considering only ions with charges of+1, +2, -1 and -2, or neutral atoms, give the symbols for 4 species that are isoelectronic with the chloride ion, Cl

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter2: Atoms And Molecules

Section: Chapter Questions

Problem 2.48PAE: A materials engineer has filed for a patent for a new alloy to be used in golf club heads. The...

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A materials engineer has filed for a patent for a new alloy to be used in golf club heads. The composition by mass ranges from 25 to 31% manganese, 6.3 to 7.8% aluminum, 0.65 to 0.85% carbon, and 5.5 to 9.0% chromium, with the remainder being iron. What are the maximum and minimum percentages of iron possible in this alloy? Use Figure 2.12 to snake a prediction about how the density of this alloy would compare with that of iron; justify your prediction.
You take three compounds, each consisting of two elements (X, Y. and/or Z), and decompose them to their respective elements. To determine the relative masses of X, Y. and Z. you collect and weigh the elements, obtaining the following data: Elements in Compound Masses of Elements 1. X and Y X = 0.4 g, Y = 4.2 g 2. Y and Z Y = 1.4 g, Z = 1.0 g 3. X and Y X = 2.0 g, Y = 7.0 g a. What are the assumptions needed to solve this problem? b. What are the relative masses of X, Y. and Z? c. What are the chemical formulas of the three compounds? d. If you decompose 21 g of compound XY, how much of each element is present?
5. A circulated U.S. quarter has a mass of 5.59 g. Express this mass in milligrams. 5.59 × 103 mg 5.59 mg 55.9 mg 559 mg
F2(g)+2e-→2F-(aq) 2.866 O3(g)+2H+(aq)+2e-→O2(g)+H2O(l) 2.076 Co3+(aq)+e-→Co2+(aq) 1.92 H2O2(aq)+2H+(aq)+2e-→2H2O(l) 1.776 Ce4+(aq)+e-→Ce3+(aq) 1.72 Au+(aq)+e-→Au(s) 1.692 PbO2(s)+4H+(aq)+SO42-(aq)+2e-→PbSO4(s)+2H2O(l) 1.691 MnO4-(aq)+8H+(aq)+5e-→Mn2+(aq)+4H2O(l) 1.507 Au3+(aq)+3e-→Au(s) 1.498 Cr2O72-(aq)+14H+(aq)+6e-→2Cr3+(aq)+7H2O(l) 1.36 Cl2(g)+2e-→2Cl-(aq) 1.358 O2(g)+4H+(aq)+4e-→2H2O(l) 1.229 MnO2(s)+4H+(aq)+2e-→Mn2+(aq)+2H2O(l) 1.224 2IO3-(aq)+12H+(aq)+10e-→I2(s)+6H2O(l) 1.195 Br2(l)+2e-→2Br-(aq) 1.066 VO2+(aq)+2H+(aq)+e-→VO2+(aq)+H2O(l) 0.991 HNO2(aq)+H+(aq)+e-→NO(g)+H2O(l) 0.983 NO3-(aq)+4H+(aq)+3e-→NO(g)+2H2O(l) 0.957 2Hg2+(aq)+2e-→Hg22+(aq) 0.92 Hg2+(aq)+2e-→Hg(l) 0.851 Ag+(aq)+e-→Ag(s) 0.800 Hg22+(aq)+2e-→2Hg(l) 0.797 Fe3+(aq)+e-→Fe2+(aq) 0.771 O2(g)+2H+(aq)+2e-→H2O2(aq) 0.695 MnO4-(aq)+2H2O(l)+3e-→MnO2(s)+4OH-(aq) 0.595 I2(s)+2e-→2I-(aq) 0.536 Cu+(aq)+e-→Cu(s) 0.521 O2(g)+2H2O(l)+4e-→4OH-(aq)…
A piece of copper has a volume of 560 L what is mass of sample in grams. For the problem it gives me 1cm^3Cu = 9g CU 9.5 x 10^21 atoms Cu= 1 Cu 1KG =1000g 1cm^3 =1mL 1L=1000cm^3 It basically wants me to write out the conversions correctly i just dont know which ones to use. Thank you so much for the help I really appreciate it.
Am I right? Calculate the mass percentage of water in the hydrate. Show the calculations. Sample 1 : 60.87% Mass of hydrate : 0.46g Mas of water : 0.28g Mass percentage of water in the hydrate = 0.28g/0.46g x 100 = 60.87% Sample 1 2 3 Calculations for sample 1 Mass of aluminum dish 1.24g 1.26g 1.24g - Mass of aluminum dish + Epsom salt 1.70g 1.94g 1.80g - Epsom salt, original (hydrated) mass 0.46g 0.68g 0.56g 1.70g – 1.24g = 0.46g Mass of aluminum dish + Epsom salt after heating 1.42g 1.62g 1.61g Epsom salt, heated (dehydrated) mass 0.18g 0.36g 0.37g 1.42g- 1.24g = 0.18g Mass of water 0.28g 0.32g 0.19g 0.46g – 0.18g = 0.28g Moles of magnesium sulfate 0.0015mol 0.0030mol 0.0031mol 0.18g x (1mol/120.37g)= 0.0015mol Moles of water 0.016mol 0.018mol 0.011mol 0.28g x (1mol/18.02g) = 0.016mol Ratio of moles water: moles of magnesium sulfate 32:3 18:3 11:3.1…
Ag+(aq)+e-→Ag(s) 0.800 Al3+(aq)+3e-→Al(s) -1.676 Au+(aq)+e-→Au(s) 1.692 Au3+(aq)+3e-→Au(s) 1.498 Ba2+(aq)+2e-→Ba(s) -2.912 Be2+(aq)+2e-→Be(s) -1.847 Br2(l)+2e-→2Br-(aq) 1.066 Ca2+(aq)+2e-→Ca(s) -2.868 Cd2+(aq)+2e-→Cd(s) -0.403 Ce4+(aq)+e-→Ce3+(aq) 1.72 Cl2(g)+2e-→2Cl-(aq) 1.358 Co2+(aq)+2e-→Co(s) -0.28 Co3+(aq)+e-→Co2+(aq) 1.92 Cr2+(aq)+2e-→Cr(s) -0.913 Cr3+(aq)+e-→Cr2+(aq) -0.407 Cr3+(aq)+3e-→Cr(s) -0.744 CrO42-(aq)+4H2O(l)+3e-→Cr(OH)3(s)+5OH-(aq) -0.13 Cr2O72-(aq)+14H+(aq)+6e-→2Cr3+(aq)+7H2O(l) 1.36 Cu+(aq)+e-→Cu(s) 0.521 Cu2+(aq)+e-→Cu+(aq) 0.153 Cu2+(aq)+2e-→Cu(s) 0.342 F2(g)+2e-→2F-(aq) 2.866 Fe2+(aq)+2e-→Fe(s) -0.447 Fe3+(aq)+e-→Fe2+(aq) 0.771 Fe3+(aq)+3e-→Fe(s) -0.037 2H+(aq)+2e-→H2(g) 0.000 2H2O(l)+2e-→H2(g)+2OH-(aq) -0.828 H2O2(aq)+2H+(aq)+2e-→2H2O(l) 1.776 Hg2+(aq)+2e-→Hg(l) 0.851 2Hg2+(aq)+2e-→Hg22+(aq) 0.92 Hg22+(aq)+2e-→2Hg(l) 0.797 I2(s)+2e-→2I-(aq) 0.536…
Ecell Mg‎2+(aq) + 2 e- -> Mg(s) Mg2 + |M‎g = - 2.372 Sn4‎+(aq) + 2 e- -> S‎n2+(aq) Sn2 + , Sn4 + |Pt = + 0.154 Cl‎2 (g) + 2 e- -> 2 Cl-(‎aq Cl-| Cl2 |Pt = +1.‎36 Whic‎h of the follo‎wing is best reduc‎ing ag‎ent for Cl2(g)? a. Mg‎(s) b. Mg‎2+(aq c. Sn4‎+(aq) d. Sn2‎+(aq
1 A)5.63,4.42,2.50,or 1.25 1 B)L,g,mol,or kg 2 A)129,0.109,86.0,or 57.5 2 B)g,mol,L,or mg
Palladium (Pd) is an element with properties similar to those of platinum. It is useful in eliminating harmful emission produce by internal combustion engines. Two students were given identical cylindrical “palladium” bars with the following data: Mass = 96.03 g; Length = 10.7 cm; Diameter = 9.82 mm; Density = 12.02 gcm-3 Show the calculations that Student K and S would do if: I) Student K was asked to determine whether his bar was made of pure palladium. II) Student S was asked to calculate the grams of ethyl alcohol (d = 0.789 gcm-3) his bar would displace.
The density of Neon (Ne) at a specific temperature and pressure is 3.21 x 10-5 lb/in3. Calculate the volume of 1.2 x 108 Ne atoms, in cm3, under these conditions. 1000 lb = 453.6 g 1 inch = 2.54 cm
11. A stack of 500 sheets of typed paper is 1.9 inches thick. The thickness, in inches, of a stack containing a mol of sheets of this paper is: Answers: a)9.27 X 10^-23 b)5.27 X 10^-20 c)1.43 X 10^-23 d)2.3 X 10^21 e)6.02 X 10^23