3. Internal Standard. A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3.473 and 10.222, respectively, in a chromatographic analysis. Then 1.00 mL of 8.47 mMS was added to 5.00 mL of unknown X, and the mixture was diluted to 10.00mL. This solution gave peak areas of 5.428 and 4.431 for X and S, respectively. (a) Calculate the response factor of the analyte. (b) Find the concentration of S (mM) in the 10.0 mL of mixed solution. (c) Find the concentration of X (mM) in the 10.0 mL of mixed solution. (d) Find the concentration of X in the original solution.
3. Internal Standard. A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3.473 and 10.222, respectively, in a chromatographic analysis. Then 1.00 mL of 8.47 mMS was added to 5.00 mL of unknown X, and the mixture was diluted to 10.00mL. This solution gave peak areas of 5.428 and 4.431 for X and S, respectively. (a) Calculate the response factor of the analyte. (b) Find the concentration of S (mM) in the 10.0 mL of mixed solution. (c) Find the concentration of X (mM) in the 10.0 mL of mixed solution. (d) Find the concentration of X in the original solution.
Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter15: Molecular Luminescence Spectrometry
Section: Chapter Questions
Problem 15.8QAP
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