A 100.0 mL solution of 0.0200 M Fe³+ in 1 M HCIO, is titrated with 0.100 M Cu* , resulting in the formation of Fe²+ and Cu²+. A Pt indicator electrode and a saturated Ag|AgCl electrode are used to monitor the titration.

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter23: Potentiometry
Section: Chapter Questions
Problem 23.24QAP
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A 100.0 mL100.0 mL solution of 0.0200 M Fe3+0.0200 M Fe3+ in 1 M HClO41 M HClO4 is titrated with 0.100 M Cu+0.100 M Cu+, resulting in the formation of Fe2+Fe2+ and Cu2+Cu2+. A PtPt indicator electrode and a saturated Ag∣∣AgClAg|AgCl electrode are used to monitor the titration.

Calculate the values of ? for the cell after each of the given volumes of the Cu+Cu+ titrant have been added.

A 100.0 mL solution of 0.0200 M Fe³+ in 1 M HCIO, is titrated with 0.100 M Cu* , resulting in the formation of Fe²+ and
Cu²+. A Pt indicator electrode and a saturated Ag|AgCl electrode are used to monitor the titration.
Transcribed Image Text:A 100.0 mL solution of 0.0200 M Fe³+ in 1 M HCIO, is titrated with 0.100 M Cu* , resulting in the formation of Fe²+ and Cu²+. A Pt indicator electrode and a saturated Ag|AgCl electrode are used to monitor the titration.
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