a At 500 K, in the presence of a copper surface, ethanol decomposes according to the equation C,H5OH(g) – CH3CHO(g) + H2(g) The pressure of C2H5OH was measured as a function of time, and the following data was obtained: Time (s) | P(C2H,ОН) (torr) 250. 100. 237 200. 224 300. 211 400. 198 500. 185 Since the pressure of a gas is directly proportional to the concentration of the gas, we can express the rate law for a gaseous reaction in terms of partial pressures. Using the preceding data, choose the correct rate law. Hint: To determine the order of the reaction with respect to C,H5OH, compare how the pressure of C,H5OH decreases with each time listing. Rate = k Rate = k[CH3CHO][H,j² Rate = k[C2H5OH][CH;CHO][H2] O Rate = k[C2H5OH]

Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter12: Kinetics
Section: Chapter Questions
Problem 43E: Some bacteria are resistant to the antibiotic penicillin because they produce penicillinase, an...
icon
Related questions
Question
a At 500 K, in the presence of a copper surface, ethanol decomposes according to the equation
C,H5OH(g) –
CH3CHO(g) + H2(g)
The pressure of C2H5OH was measured as a function of time, and the following data was obtained:
Time (s) | P(C2H,ОН) (torr)
250.
100.
237
200.
224
300.
211
400.
198
500.
185
Since the pressure of a gas is directly proportional to the concentration of the gas, we can express the rate law for a gaseous reaction in terms of partial pressures.
Using the preceding data, choose the correct rate law. Hint: To determine the order of the reaction with respect to C,H5OH, compare how the pressure of C,H5OH decreases with each time listing.
Rate = k
Rate = k[CH3CHO][H,j²
Rate = k[C2H5OH][CH;CHO][H2]
O Rate = k[C2H5OH]
Transcribed Image Text:a At 500 K, in the presence of a copper surface, ethanol decomposes according to the equation C,H5OH(g) – CH3CHO(g) + H2(g) The pressure of C2H5OH was measured as a function of time, and the following data was obtained: Time (s) | P(C2H,ОН) (torr) 250. 100. 237 200. 224 300. 211 400. 198 500. 185 Since the pressure of a gas is directly proportional to the concentration of the gas, we can express the rate law for a gaseous reaction in terms of partial pressures. Using the preceding data, choose the correct rate law. Hint: To determine the order of the reaction with respect to C,H5OH, compare how the pressure of C,H5OH decreases with each time listing. Rate = k Rate = k[CH3CHO][H,j² Rate = k[C2H5OH][CH;CHO][H2] O Rate = k[C2H5OH]
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Similar questions
Recommended textbooks for you
Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:
9781938168390
Author:
Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:
OpenStax
Chemistry: Principles and Practice
Chemistry: Principles and Practice
Chemistry
ISBN:
9780534420123
Author:
Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781133611097
Author:
Steven S. Zumdahl
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning