A man and a woman do not have hemophilioa, but the womans father did. (Hemophilia is X-linked recessive). a) What is the probability that they will have a child with hemophilia? b) Is it possible for any of their daughters to be affected? Explain.

A man and a woman do not have hemophilioa, but the womans father did. (Hemophilia is X-linked recessive). a) What is the probability that they will have a child with hemophilia? b) Is it possible for any of their daughters to be affected? Explain.

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Description: I will be adding two questions here because I asked two of the same questions twice by accident earlier. A man and a woman do not have hemophilioa, but the womans father did. (Hemophilia is X-linked recessive).a) What is the probability that they wil

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter6: Cytogenetics: Karyotypes And Chromosome Aberrations

Section: Chapter Questions

Problem 2QP: Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the...

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Joe has classic hemophilia, an X-linked recessive disease. Could Joe have inherited the gene for this disease from the following people? Yes No a. His mother’s mother ____________ ____________ b. His mother’s father ____________ ____________ c. His father’s mother ____________ ____________ d. His father’s father ____________ ____________
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Hemophilia is an X-linked recessive gene. A normal woman who is a carrier for hemophilia marries a man with hemophilia. Draw a punnett square of a cross between these two individuals. What are the chances that this couple will have a daughter with hemophilia?
Hemophilia A is caused by a recessive X-linked allele that encodes a defective form of a clotting protein. If a affected father and a mother who is known to not be a carrier have children, what percentage of female offspring will have hemophilia?
A mother is heterozygous for the X-linked gene for colorblindness and also heterozygous for the autosomal inherited sickle cell anemia. She is married to a man who can see color normally and who is heterozygous for sickle cell trait. Using b (colorblind), B (normal color), S (normal hemoglobin), s (sickle cell), answer the following: a. What are the genotypes of the parents? b: What is the probability of having a child who is both color blind and has sickle cell anemia?
A form of hemophilia is caused by a sex-linked (X-linked) recessive gene. A phenotypically normal woman whose father had hemophilia marries a man who suffers with hemophilia. What is the probability that their first daughter will have hemophilia?
A color-blind man marries a woman with normal vision whose father was color-blind. Remember that color-blindness is an X-linked recessive trait. Hint: see figure 12.7 in book. A) What is the probability that their first child will be a color-blind daughter? B) What is the probability that their first son will be color-blind?
Sickle cell anemia is caused by an individual carrying two recessive copies of the hemoglobin gene (hemoglobin gene is labeled Hb, and the recessive version is Hbs). Thus, to have sickle cell anemia, a person must have the genotype HbSHbS. A person that is HbAHbA carries two copies of the normal hemoglobin gene and does not have sickle cell anemia. A person that is heterozygous (HbAHbS) produces enough normal hemoglobin to not have sickle cell anemia but is also resistant to malaria. People that are heterozygous are called “carriers” because they carry the recessive allele but do not express the recessive phenotype. a. A couple are both resistant to malaria but do not have sickle cell anemia. Draw a Punnett square to represent this cross. b. What is the probability that the couple has three children where one child does not have a recessive allele, one child is resistant to malaria and does not have sickle cell anemia, and one child has sickle cell anemia?
Jan and Michael are both carriers for the cystic fibrosis allele. If Jan and Michael have five children, what the probability that three or more of the children will have the disease?