Abs vs Time Trial 1 Ln(Abs) vs Time Trial 1 1/Abs vs Time Trial 1 0.35 0.00 9.00 20 40 60 80 100 120 140 160 180 8.00 y= 0.0297x + 2.4624 R=0.989 0.3 y=-0.0012x + 0.3231 -a.s0 7.00 R= 0.9771 0.25 y=0.0059x - 1.0624 6.00 0.2 -1.00 R0.9993 5.00 0.15 4.00 . .. -1.50 3.00 0.1 2.00 0.05 -2.00 1.00 0.00 20 40 60 80 100 120 140 160 180 -2.50 20 40 60 80 100 120 140 160 180

Abs vs Time Trial 1 Ln(Abs) vs Time Trial 1 1/Abs vs Time Trial 1 0.35 0.00 9.00 20 40 60 80 100 120 140 160 180 8.00 y= 0.0297x + 2.4624 R=0.989 0.3 y=-0.0012x + 0.3231 -a.s0 7.00 R= 0.9771 0.25 y=0.0059x - 1.0624 6.00 0.2 -1.00 R0.9993 5.00 0.15 4.00 . .. -1.50 3.00 0.1 2.00 0.05 -2.00 1.00 0.00 20 40 60 80 100 120 140 160 180 -2.50 20 40 60 80 100 120 140 160 180

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter33: Automated Methods Of Analysis

Section: Chapter Questions

Problem 33.4QAP

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You are absolutely the BEST. Finally someone that dosen't calculate this exercise as 836f66dgsffjgvkik!!!! I understand everything you did, but I have one question. Some experts says that km can be calculated by saying Vmax from date divided by 2 and then they find Km by going down on x-axis on the graph. But, you used the MM equation, to solve for Km. Is both method the same? Or is one of them more precise than the other? *And if theres no need to reply back after you answering my question, then I will thank you again for your help. I have more these types of exam questions that I will probably upload later, and I hope someone like you will look at it.
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