Calculate the mean and 90% confidence interval for the data set. Sample Value 8.0626 8.0650 3 8.0583 4 8.0564 8.0571 6. 8.0600 mean: 山T四月@ stv A hulu
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- The following molarities were calculated from replicate standardization of a solution: 0.5006, 0.5003, 0.5023, 0.5009, 0.5015, 0.5013, and 0.5022 M. Assuming no determinate errors, what is the upper limit of the 95% confidence interval?The following molarities were calculated from replicate standardization of a solution: 0.5022, 0.5022, 0.5021, 0.5008, upper limit of the 95% confidence interval?Plot the following data and perform linear regression to obtain the value of the slope, the value of the y-intercept, and the correlation coefficient r. x- axis y-axis ln(0) 4.6052 0.0000 3.8712 0.6931 3.4012 1.0986 2.7081 1.3863 2.1972 1.6094 1.7918 1.7918 1.0986 1.9459 0.0000
- An analyst obtained the following data for the percent compound Z in triplicates (n=3) of an insecticide preparation: 7.47, 6.98, and 7.27. Calculate the 90% confidence limit for the mean of the data assuming that only information about the precision of the method is the precision for the three data points.y= mx+ b Slope () = -4E-09 y-intercept () = 0.4021 and OD= 0.540 , Calculate the concentration (x)Calculate the following exercise with correct sig figs: ((2.9365mL - 3.00mL)/3.00mL)x100%
- A chemist obtained the following data for the percent compound Z in triplicates (n=3) of an insecticide preparation: 7.47, 6.98, and 7.27. Calculate the 90% confidence limit for the mean of the data assuming that only information about the precision of the method is the precision for the three data points.What do you understand by Isocratic and Gradient elution?A standard solution was prepared containing 10.0 ppm of an analyte and 15.0 ppm of an internal standard. Analysis of the sample gave signals for the analyte and internal standard of 0.155 and 0.233 (arbitrary units), respectively. Sufficient internal standard was added to an unknown sample to make it 15.0 ppm in the internal standard. Analysis of the unknown sample yielded signals for the analyte and internal standard of 0.274 and 0.198, respectively. Calculate the concentration of analyte in the unknown sample.
- 5 0.0030 0.0015 0.0005 6 0.0030 0.0057 0.0089 7 0.0086 0.0057 0.0089 Show the Calculations of Qc and Kc for Exp. 5-7 Please help me out. ThanksI have set up my spreadsheet using this sample data and reproduced the result with a pKa of 4.64. true or falseMeasurements of boiling temperatures of samples of a liquid (°C) are given below: 78.4 79.0 78.8 79.2 78.6 Calculate the meanCalculate the modeCalculate the standard deviation