After the neutralization reaction of 42% 0.5 mL nitric acid and 0.28M 18 mL sodium hydroxide, a temperature increase of 15 ° C was observed and the temperature value was determined as 825 cal. According to these results; a) Number of moles of neutralized base ................. ...................... b) Reaction enthalpy .................. ................. Reaction according to enthalpy value ................ .................. c) The constant of the calorimeter in terms of water ............................ ..................... (d (HNO3) = 1.51g / mL; M (HNO3) = 63.01 g / mol) Note: enter only required numerical values and units in the spaces in the question.
After the neutralization reaction of 42% 0.5 mL nitric acid and 0.28M 18 mL sodium hydroxide, a temperature increase of 15 ° C was observed and the temperature value was determined as 825 cal. According to these results; a) Number of moles of neutralized base ................. ...................... b) Reaction enthalpy .................. ................. Reaction according to enthalpy value ................ .................. c) The constant of the calorimeter in terms of water ............................ ..................... (d (HNO3) = 1.51g / mL; M (HNO3) = 63.01 g / mol) Note: enter only required numerical values and units in the spaces in the question.
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter18: Chemical Kinetics
Section: Chapter Questions
Problem 65AP
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After the neutralization reaction of 42% 0.5 mL nitric acid and 0.28M 18 mL sodium hydroxide, a temperature increase of 15 ° C was observed and the temperature value was determined as 825 cal. According to these results;
a) Number of moles of neutralized base ................. ......................
b) Reaction enthalpy .................. ................. Reaction according to enthalpy value ................ ..................
c) The constant of the calorimeter in terms of water ............................ .....................
(d (HNO3) = 1.51g / mL; M (HNO3) = 63.01 g / mol)
Note: enter only required numerical values and units in the spaces in the question.
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