Aluminum reacts with chlorine gas to form aluminum chloride via the formula pattern: 2Al + 3Cl2 ➝ 2AlCl3 a. Identify the limiting reagent b. How many grams of aluminum chloride could be produced from 34.0g of aluminum and 39.0g of chlorine gas? c. What mass of excess reagent remains in the reaction?
Aluminum reacts with chlorine gas to form aluminum chloride via the formula pattern: 2Al + 3Cl2 ➝ 2AlCl3 a. Identify the limiting reagent b. How many grams of aluminum chloride could be produced from 34.0g of aluminum and 39.0g of chlorine gas? c. What mass of excess reagent remains in the reaction?
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter3: Mass Relations In Chemistry; Stoichiometry
Section: Chapter Questions
Problem 66QAP: Chlorine and fluorine react to form gaseous chlorine trifluoride. Initially, 1.75 mol of chlorine...
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Aluminum reacts with chlorine gas to form aluminum chloride via the formula pattern: 2Al + 3Cl2 ➝ 2AlCl3
a. Identify the limiting reagent
b. How many grams of aluminum chloride could be produced from 34.0g of aluminum and 39.0g of chlorine gas?
c. What mass of excess reagent remains in the reaction?
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