   # 4.27 Copper reacts with sulfuric acid according to the following equation: 2 H 2 SO 4 + Cu → CuSO 4 + 2 H 2 O + SO 2 How many grams of sulfur dioxide are created by this reaction if 14.2 g of copper reacts with 18.0 g of sulfuric acid? ### Chemistry for Engineering Students

4th Edition
Lawrence S. Brown + 1 other
Publisher: Cengage Learning
ISBN: 9781337398909 ### Chemistry for Engineering Students

4th Edition
Lawrence S. Brown + 1 other
Publisher: Cengage Learning
ISBN: 9781337398909
Chapter 4, Problem 4.27PAE
Textbook Problem
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## 4.27 Copper reacts with sulfuric acid according to the following equation:   2 H 2 SO 4 +  Cu →  CuSO 4 +  2 H 2 O  +  SO 2 How many grams of sulfur dioxide are created by this reaction if 14.2 g of copper reacts with 18.0 g of sulfuric acid?

Interpretation Introduction

Interpretation:

Grams of sulphur dioxide created by the given reaction needed to be determined.

Concept introduction:

• The maximum yield is obtained by reacting all the limiting reactant.

Given:

m = 14.2 gCum = 18.0 gH2SO4

### Explanation of Solution

Use the given amounts to identify the limiting reactant. Then calculate the total amount of possible iron yield.

Step 1: Balance Reaction

Step 2: Change all mass units to mol units

Molecular WeightCu=63.546 g/molMolecular WeightH2SO4=98.08g/molMolecular Weight of  SO2=64.06g/mol

molH2SO4=massH2 SO4Molecular WeightH2 SO4=18.098.08=0.1835molCu=massCuMolecular WeightCu=14.263.55=0.223

Step 3: Relate stoichiometry

Ratio=2

Step 4: Actual Ratio

Ratio = mol H2SO4molCu = 0.18350

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