Assume that the experiments performed in the absence of inhibitors were conducted by adding 5 μL of a 2 mg/mL enzyme stock solution to an assay mixture with a total volume of 1 mL. Take into account that XYZase is a monomeric enzyme with a molecular mass of 45,000 Daltons. Hint: To calculate the ???? in units of per second (s−1), you must first determine the ???? in micromoles per second (μmol/sec).   Please explain step by step

Biochemistry
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Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
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Assume that the experiments performed in the absence of inhibitors were conducted by adding 5 μL of a 2 mg/mL enzyme stock solution to an assay mixture with a total volume of 1 mL. Take into account that XYZase is a monomeric enzyme with a molecular mass of 45,000 Daltons.

Hint: To calculate the ???? in units of per second (s−1), you must first determine the ???? in micromoles per second (μmol/sec).

 

Please explain step by step

INITIAL INVESTIGATION
Run kinetics experiments on XYZase without inhibitors and with Compound X.
Results: The compound found in Dr. Bleu's coffee (Compound X) has yet to be identified. Using a small amount of the
compound extracted from the coffee, you have discovered that it is an inhibitor of XYZase. Given this revelation, it seems
clear that this compound is most likely the murder weapon. The data you have gathered is shown in Table 1.
Table 1
[S]
(nM)
50
75
150
400
Vo (no inhibitor)
(umol)
0.14
0.19
0.32
0.47
Vo (Compound X)
(umol)
0.040
0.050
0.080
0.14
Note: [S] is given in nM; other values represent observed Vo values given in units of µmol product formed per minute.
A Lineweaver-Burk plot made from the data without an inhibitor is shown in Graph 1.
Transcribed Image Text:INITIAL INVESTIGATION Run kinetics experiments on XYZase without inhibitors and with Compound X. Results: The compound found in Dr. Bleu's coffee (Compound X) has yet to be identified. Using a small amount of the compound extracted from the coffee, you have discovered that it is an inhibitor of XYZase. Given this revelation, it seems clear that this compound is most likely the murder weapon. The data you have gathered is shown in Table 1. Table 1 [S] (nM) 50 75 150 400 Vo (no inhibitor) (umol) 0.14 0.19 0.32 0.47 Vo (Compound X) (umol) 0.040 0.050 0.080 0.14 Note: [S] is given in nM; other values represent observed Vo values given in units of µmol product formed per minute. A Lineweaver-Burk plot made from the data without an inhibitor is shown in Graph 1.
A Lineweaver-Burk plot made from the data without an inhibitor is shown in Graph 1.
8
1/V/
X-
7
6
LO
5
4
3+
2
-0.01 -0.005 0
-1
-2
-f
0.005
0.01
● Data point
0.015 0.02 0.025
1/[S]
Graph 1
Trend line
y = 291x + 1.32
Transcribed Image Text:A Lineweaver-Burk plot made from the data without an inhibitor is shown in Graph 1. 8 1/V/ X- 7 6 LO 5 4 3+ 2 -0.01 -0.005 0 -1 -2 -f 0.005 0.01 ● Data point 0.015 0.02 0.025 1/[S] Graph 1 Trend line y = 291x + 1.32
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