7 of 10>Atomic absorption spectroscopy was used to determine the amount of aluminum in a sample of sunscreen. A blank solution wasmeasured seven times to determine the detection and quantitation limits of the spectrometer. The blank readings were: 0.0073,0.0082, 0.0110, 0.0101, 0.0102, 0.0098, and 0.0090 AU. Determine the signal at the detection limit and the signal at the limit ofquantitation for this method.signal detection limit:signal limit of quantitation:huluétv14

The measured blank values are: 0.0073, 0.0082, 0.0110, 0.0101, 0.0102, 0.0098, and 0.0090 AU number…

Answered: Atomic absorption spectroscopy was used…

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter9: Atomic Absorption And Atomic Fluorescence Spectrometry

Section: Chapter Questions

Problem 9.8QAP

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Thienothiophene and sexithiophene are conjugated molecules used in printed organic electronics. A chlorobenzene solution of equal concentrations of the two molecules was prepared and its absorbance was recorded with a 0.01 cm sample cell to give 0.88 % transmittance (T) at 400 nm. Calculate the concentration of each of the molecules given that the molar absorption coefficient of the thienothiophene is 23,000 L.mol-1cm-1 and the sexithiophene is 34,000 L.mol-1cm-1. Remember that absorbance is additive.
When a sample of 4-heptanone was irradiated for 100 sec with 313 nm radiation with a power output of 50 W under conditions of total absorption, it was found that 2.8 mmole C2H4 was formed. What is the quantum yield for the formation of ethane?
Inductively coupled plasma–optical emission spectrometry (ICP-OES) was used for the determination of cadmium using indium as an internal standard. A solution containing 2.15 ppm Cd2+ and 5.76 ppm In3+ gave signals of 19,291 and 37,190 counts for cadmium and indium, respectively. A 0.01652 g sample was dissolved in acid and quantitatively transferred to a 250.0 mL volumetric flask. A 1.00 mL aliquot of 264.5 ppm In3+ was added and the flask was diluted to volume with deionized water. ICP-OES analysis of the sample solution gave signals of 31,109 and 118,941 counts for cadmium and indium, respectively. What was concentration of the Cd2+ in the sample? Give answer all questions with explanation
Exactly 10.00-mL aliquots of a solution containing phenobarbital were measured into 50.00-mL volumetric flasks and made basic with KOH. The following volumes of a standard solution of phenobarbital containing 2.000μg/mL of phenobarbital were then introduced into each flask and the mixture was diluted to volume: 0.000, 0.500, 1.00, 1.50, 2.00 mL. The fluorescence of each of these solutions was measured with a fluorimeter, which gave values of 3.26, 4.80, 6.41, 8.02, 9.56, respectively. a. plot the data. b. derive a least squares equation for the data plotted in (a). c. find the concentration of phenobarbital from the equation in (b). d. calculate a standard deviation for the concentration obtained in (c).
An absorbance calibration curve for Zn was fitted to equation A = 0.913×`Zn, ppm`. Flask 1: To the first flask, a 1.00 mL aliquot of the unknown Zn solution was diluted to 100.0 mL in a volumetric flask; the absorption intensity from this sample was measured to be A = 0.204. Flask 2: To a second flask, a 1.00 mL aliquot of the unknown Zn sample and a 1.00 mL aliquot of 10.00 ppm Zn solution were added and diluted to 100.0 mL in a volumetric flask; the absorbance of this sample was measured to be A = 0.294. Calculate the % spike recovery for the analysis and report to the nearest whole number. Hint: A=mC of the type y=mx, so C=A/m %Spike=100%((Cspike-Coriginal)/Cadded)) Cadded can be found from C1 V1=Cadded V2.
Potassium dichromate (K2Cr2O7) and potassium permanganate (KMnO4) give overlapping UV-Vis absorption spectra in 1 M sulphuric acid. K2Cr2O7 shows an absorption maximum at 440 nm and KMnO4 shows the absorption maximum at 545 nm . An unknown sample solution containing a mixture of K2Cr2O7 and KMnO4 was analyzed using a 1-cm cell and the absorbance values at these two wavelengths were as follows: A440 = 0.515 and A545 = 0.835 The absorbance values for standard solutions of K2Cr2O7 (1.00 x 10-3 M) and KMnO4 (2.00 x 10-4 M) in 1 M sulphuric acid using the same 1 cm cell were as follows: Calculate the concentrations of K2Cr2O7 and KMnO4 in the unknown sample.
Below is given the FT-IR (Fourier Transform Infra Red) data of a 1:1 (by weight) mixture of ethylene carbonate (EC) and dimethyl carbonate (DMC). Absorbance Pis given as a function of wavenumber, m. Regress the above data to a second order polynomial P = a, + a, m+ az m? Find the absorbance at m = 1000 cm-1 Wavenumber, m Absorbance, P (arbitrary unit) ( cm-1) 804.184 0.1591 827.326 0.0439 846.611 0.0050 869.753 0.0073 889.038 0.0448 892.895 0.0649 900.609 0.1204
The molecule with strong absorptions at 1800 and 1760 cm ^ -1 is:
To determine the content of Pb in a canned sausage, 5.00 g were weighed and after adequate treatment they were gauged to a volume of 100 mL, from there an aliquot of 2 mL was taken and brought to a volume of 250 mL. The readings of a series and of the sample were taken in an Atomic Absorption spectrophotometer, recording the following data: mg Pb/mL 0 1 2 3 4 Sample Absorbance 0.00 0.15 0.29 0.44 0.58 0.38 What is the% Pb in canned sausage?
6 Why standard solutions are used in Atomic absorption Spectroscopy (AAS) whereas UV-Vis molecular absorbance only extinction coefficient is necessary?

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