Based on your answer to part (a), which of the following statements is true?
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Q: (NINETEEN)
A: The information provided in the are as follows :-Level of significance
PART B
____ Since the p- valueis less than the significance level, the null hypothesis is rejected.
_____ Since the p- valueis less than the significance level, the null hypothesis is not rejected.
____ Since the p- valueis greater than the significance level, the null hypothesis is rejected.
___ Since the p- valueis greater than the significance level, the null hypothesis is not rejected.
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- a consumer group claims that the mean acceleration time from 0 to 60 miles per hour for a sedan is 6.3 seconds. A random sample of 33 sedans has a mean acceleration time from 0 to 60 miles per hour is 7.2 seconds. Assume that the population standard deviation is 2.5 seconds.At alpha = 0.05, can you reject the claim?1. In a random sample of fishes from a pond, the mean tail length was 6.0 mm and the reference tail length for the species was found to be 4.0 mm with a standard deviation of 2.0. if there are 16 fishes, what would be the z score and which hypothesis would be accepted? 2. If the mean for group 1 in a clinical trial for the time for a drug X to act is 10 minutes and 8 minutes for group 2 and if the standard deviation for group 1 is 1.0 and group 2 is 2.0. If there are 4 persons in both groups, what is the t value and which hypothesis would you accept if t critical is 3.14 ( 2 sided) 3. A geneticist is examining the relationship between genotype and phenotype for roses. He calculated a chi-square value of 4.1 for a 2 x 2 table. If the scenario is two sided, which hypothesis did he accept? 4.It is claimed that 75% of puppies are house-trained by the time they are 6 months old. To investigate this claim, a random sample of 50 puppies is selected. It is discovered that 42 are house-trained by the time they are 6 months old. A trainer would like to know if the data provide convincing evidence that greater than 75% of puppies are house-trained by the time they are 6 months old. The standardized test statistic is z = 1.47 and the P-value is 0.0708. What conclusion should be made using the = 0.05 significance level? Because the P-value is greater than = 0.05, there is convincing evidence that 75% of puppies are house-trained by the time they are 6 months old. Because the P-value is greater than = 0.05, there is not convincing evidence that 75% of puppies are house-trained by the time they are 6 months old. Because the P-value is greater than = 0.05, there is convincing evidence that greater than 75% of puppies are house-trained by the time they are 6 months old. Because…
- A statistics student randomly selected 45 packets of sugar and weighed the contents of each packet, getting a mean of 3.586 grams and a standard deviation of 0.194 grams. Test the claim that the weights of the sugar packets have a mean no longer equal to 3.5 grams, as indicated on the label. Let "alpha" be 0.10 to test this claim. What are the hypotheses to be tested?The sample mean and standard deviation from a random sample of 30 observations from a normal population were computed as x¯=31x¯=31 and s = 9. Calculate the t statistic of the test required to determine whether there is enough evidence to infer at the 3% significance level that the population mean is greater than 28. Test Statistic =A sample of 20 elements selected from a population produced a mean of 65 and a standard deviation of 9. Another sample of 25 elements selected from another population produced a mean of 58 and a standard deviation of 11. Assume that the two populations are normally distributed and the standard deviations of the two populations are equal. The null hypothesis is that the means of the two populations are equal and the alternative hypothesis is that the means of the two populations are not equal. The significance level is 5%. The critical values of t are: a. –2.014 and 2.014 b. –2.017 and 2.017 c. –1.681 and 1.681 d. –1.679 and 1.679
- A random sample of 46 adult coyotes in a region of northern Minnesota showed the average age to be x = 2.01 years, with sample standard deviation s = 0.72 years. However, it is thought that the overall population mean age of coyotes is μ = 1.75. Do the sample data indicate that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years? Use α = 0.01. State the null and alternate hypotheses. H0: μ < 1.75 yr; H1: μ = 1.75 yr H0: μ > 1.75 yr; H1: μ = 1.75 yr H0: μ = 1.75 yr; H1: μ ≠ 1.75 yr H0: μ = 1.75 yr; H1: μ > 1.75 yr H0: μ = 1.75 yr; H1: μ < 1.75 yr (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. The standard normal, since the sample size is large and σ is known. The Student's t, since the sample size is large and σ is unknown. The standard normal, since the sample size is large and σ is unknown. The Student's t, since the sample size is large and σ is known. What…If the null hypothesis Ho : mean = 17.0 is rejected at alpha = 0.01 when a mean of 21.0 is obtained from a random sample, ?An auto manufacture claims that the variance of the gas mileages in a model of hybrid vehicle is 0.16. A random sample of 30 vehicles has a varience of 0.26. At a=0.05 is there enough evidence to reject the claim??
- It is known that the volume of containers of a specific lubricant is normally distributed with a variance of 0.03 liters. Test the hypothesis that o^2 is not equal to 0.03 for the random sample of 10 containers with s = 0.24585 l. Use a P-value in your conclusions. Note:In the image, this is the exercise in Spanish, which is the original, to make it more understandable.John rejected a null hypothesis in a right-tailed test for a mean at alpha = 0.025 because the critical T value was 2.000 and his calculated T value was 2.345. We can be sure that: a.) John did not commit type 1 error B.) John committed neither type 1 nor type 11 error c.) none of the presented answers is correct because none can definitely be concluded d.) John did not commit type 11 errorA researcher knew that before cell phones, a person made on average 3.2 calls per day. He believes that the number of calls made per day today is higher. He selects a random sample of 28 individuals who use a cell phone and asks them to keep track of the number of calls that they made on a certain day. The mean was 3.5. At (alpha) = 0.01, is there enough evidence to support the researchers claim? The standard deviation for the population found by a previous study is 0.9. Assume that the variable is normally distributed. Use the critical value method with tables. A. State the hypotheses and identify the claim with the correct hypothesis. B. Find the critical value(s). C. Compute the test value. D. Make the decision. E. Summarize the results.