Calculate the percent yield of the reaction if 1.88 g of aspirin (acetylsalicyclic) were obtained

Introductory Chemistry: A Foundation
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Calculate the percent yield of the reaction if 1.88 g of aspirin (acetylsalicyclic) were obtained

Given: Mass of salicylic acid reacting = 2.45 g.
Moles of salicylic acid reacting
M
From the balanced reaction, we can see that 1
mole of salicylic acid is reacting to produce 1
mole of aspirin.
Hence moles of aspirin produced = moles of
salicylic acid reacting = 0.017737 mol.
Therefore the mass of aspirin formed
theoretically = moles x molar mass =
0.017737 x 180.17 = 3.20 g approx.
Hence the answer is 3.20 g approx.
Transcribed Image Text:Given: Mass of salicylic acid reacting = 2.45 g. Moles of salicylic acid reacting M From the balanced reaction, we can see that 1 mole of salicylic acid is reacting to produce 1 mole of aspirin. Hence moles of aspirin produced = moles of salicylic acid reacting = 0.017737 mol. Therefore the mass of aspirin formed theoretically = moles x molar mass = 0.017737 x 180.17 = 3.20 g approx. Hence the answer is 3.20 g approx.
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