Calculate the standard molar enthalpy of the global reaction of acetylene (C,H): 2C(graphite) + H2(e) > C2H2(e) From the corresponding enthalpy equations and values: (1) Cigraphite) + O2(g) → CO2(g) A,Hº = - 393.5 kJ mol-1 (2) H2le) + ½ O2le) > H,O) > H2O1) A,H° = - 285.8 kJ mol-1 (3) 2C2H2(e) + 502(8) → 4CO2(8) + 2H20) A,H° = - 2598.8 kJ mol-1

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
Section: Chapter Questions
Problem 96QRT
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Calculate the standard molar enthalpy of the global reaction of
acetylene (C,H,):
20(graphite) + H2(g)→ C,H2(g)
From the corresponding enthalpy equations and values:
(1) C(graphite) + O2(g) → CO2(e)
A,Hº = - 393.5 kJ mol·1
(2) H2(e) + ½ 02(g) → H2O1)
A,Hº = - 285.8 kJ mol-1
(3) 2C,H2(g) + 502(e)
> 4CO2(e) + 2H,01)
A,H° = - 2598.8 kJ mol-1
Transcribed Image Text:Calculate the standard molar enthalpy of the global reaction of acetylene (C,H,): 20(graphite) + H2(g)→ C,H2(g) From the corresponding enthalpy equations and values: (1) C(graphite) + O2(g) → CO2(e) A,Hº = - 393.5 kJ mol·1 (2) H2(e) + ½ 02(g) → H2O1) A,Hº = - 285.8 kJ mol-1 (3) 2C,H2(g) + 502(e) > 4CO2(e) + 2H,01) A,H° = - 2598.8 kJ mol-1
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