Consider the equilibrium: Sno, (s) + 2CO (8)Sn (s) + 2C02 (8)5.0g of tin (II) oxide and 0.85 M carbon monoxide were initially charged in a closed reactor atroom temperature and allowed to reach equilibrium. At equilibrium 0.65 M of CO wasmeasured. Calculate Kc for the equilibrium.O 0.09504.2O0.033O0.22

The equilibrium reaction can be written as: SnO2 (s) +…

Answered: Consider the equilibrium: Sno, (s) +…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 12.ACP

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Nitrogen, hydrogen, and ammonia are in equilibrium in a 1000-L reactor at 550 K. The concentration of N2 is 0.00485 M, H2 is 0.022 M, and NH3 is 0.0016 M. The volume of the container is halved, to 500 L. (a) Calculate the equilibrium constant. (b) Define y as the change in the concentration of nitrogen in the 500-L container. Is y positive or negative? (c) Write the iCe table and express the equilibrium constant in a polynomial in terms of y.
Given the reaction: CO2(g) + H2(g) ⇌ H2O(g) + CO(g) If Kc = 1.6 at 1263 K, calculate the number of moles of carbon monoxide gas (CO) in the final equilibrium system obtained by initially adding 1.00 mol of H2, 2.00 mol of CO2, 0.750 mol of H2O, and 1.00 mol of CO to a 5.00 L reactor at the given temperature.
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i think it is The reaction quotient can be calculated from the reactants' and products' concentrations or partial pressures. 2 SmCl3(aq) + 6 Li(aq) → 2 Sm(s) + 6 LiCl(aq) At non-standard conditions, the concentrations are: [SmCl3] = 2.00 M [Li] = 2.00M [Sm] = 0 (solid) [LiCl] = 0.0100 M The reaction quotient (Q) can be calculated as follows: Q = {[LiCl]^6}/[Sm3+ ]^2[Cl3]^2 = (0.0100)^6 /(2.00)^2 x (2.00)^2 = 6.25 x 10^-14
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In the gas phase reaction 2 A(g) + B(g) = 3 C (g) + 2 D (g) it was found that when 1.00 mol A, 2.00 mol B and 1.00 mol D were mixed and allowed to come to equilibrium at 25oC, the resulting mixture contained 0.9 mol C at a total pressure of 1.00 bar. Calculate (a) the mole fractions of each species, (b) KX, (c) KP and (d) △Go . Answer: [0.087 (A); 0.370 (B); 0.196 (C); 0.348 (D); 0.326; 0.325; 2.76 kJ]
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C6H12O6(aq) + 6O2(g) 6CO2(g) + 6H2O(l)ΔH = –2802.7 kJ mol –1a) Write an expression for the equilibrium constant for this reaction.b) At equilibrium, the concentration of the reactants and products are determined as [CO2] = 0.30 M, [O2] = 0.040 M and [C6H12O6] = 0.065 M. Determine the value of the equilibrium constant (Kc) and predict the whether the products or reactants will be favoured at equilibrium.c) Given that the concentrations of the reactants and products at a particular time are [CO2] = 0.65 M, [O2] = 0.020 M and [C6H12O6] = 0.055 M, determine the reaction quotient (Qc). Compare the Kc and Qc values and predict the favoured direction of the reaction.d) Explain the effect on equilibrium of:i) Increasing temperatureii) Increasing pressureiii) Decreasing the concentration of oxygeniv) Increasing the concentration of carbon dioxidev) Adding a catalyst

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