Consider the following recursive algorithm. ALGORITHM Riddle(A[0..n-1]) Ilnput:AnarrayA[0.n-1]of real numbers if n =1 returnA[0] else temp-Riddle(A[0..n-2]) if temp < A[n-1] return temp else returnA[n-1] a. What does this algorithm compute? b. Set up a recurrence relation for the algorithm's basic operation count and solve it.

You want to design an algorithm, called minMax(A,p,r), that takes an array of integers and indexes of the first and last elements, and returns the minimum and maximum values in that range. Now write the pseudo code of a divide and conquer (and therefore, recursive) algorithm with the same time complexity (Θ(n)). You can assume that p ≤ r. Also, in your code, you can return two numbers by returning a pair, e.g. “return (a, b)”, and can save the output in a similar way, e.g. “(a, b) = minMax(parameters)”. (Short answer please)

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Give a recursive algorithm which takes as input a sequence of numbers and returns the minimum (i.e., smallest) member in the sequence. Your algorithm should not use an iterative loop. FindMin (al, a2,..., an) If (length (alan) = 1), Return (_A_) m: FindMin (al an-1) // The recursive call If (an S m) Else End-if Return (_B__) Return (_C_)