Consider the reaction: NH₂Cl (s) → NH₂ (g) + HCl (g) 3 -1 AS = 85.7 J K ¹mol™¹, AH = 175.96 kJ/mol 9 3 d) A gas mixture of total pressure 56 kPa consisting of 1 part NH₂ to 1 part HCl was obtained in the reaction above. Calculate the partial pressure of NH3 and HCl gas in the gas mixture. e) How much work is done when a piston is compressed from 9.87 L to 2.56 L under constant atmospheric pressure (1.013 × 10³ Pa)? f) What intermolecular forces will be dominant between NH₂ molecules?

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Chapter2: The First Law Of Thermodynamics
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Consider the reaction:
NH₂Cl (s) →>> NH₂ (g) + HCl (g)
3
AS = 85.7 J K¯¨¹mol™¹, AH = 175.96 kJ/mol
d) A gas mixture of total pressure 56 kPa consisting of 1 part NH₂ to 1 part HCl was
obtained in the reaction above. Calculate the partial pressure of NH3 and HCl gas
in the gas mixture.
e) How much work is done when a piston is compressed from 9.87 L to 2.56 L under
constant atmospheric pressure (1.013 × 10³ Pa)?
f) What intermolecular forces will be dominant between NH₂ molecules?
Transcribed Image Text:Consider the reaction: NH₂Cl (s) →>> NH₂ (g) + HCl (g) 3 AS = 85.7 J K¯¨¹mol™¹, AH = 175.96 kJ/mol d) A gas mixture of total pressure 56 kPa consisting of 1 part NH₂ to 1 part HCl was obtained in the reaction above. Calculate the partial pressure of NH3 and HCl gas in the gas mixture. e) How much work is done when a piston is compressed from 9.87 L to 2.56 L under constant atmospheric pressure (1.013 × 10³ Pa)? f) What intermolecular forces will be dominant between NH₂ molecules?
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