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![I
Data Report Sheet: Spectrophotometric Determination of an Equilibrium
Coustant.
Part A: Determination of a Calibration Curve:
Std. 2
Stnd. 3
Stnd 4
Stnd. 5
Stnd. 6
(H)
0.000189 0.000204
0.000127
(Fe(SCN)"]
Column A
0.
0600000
0.432
0.480
0.633
0.831
0.887
Absorbance
Column E
y3 4339.8x + 0.0258
Equafion of Calibration Line:
Correlation Coefficient:
4339.8
Slope (be):
Part B: Determination of K
Expt. 1
Expt. 2
Expt. 3
Expt. 4
Expt. 5
0.00165
0.00165
0.00165
0.00165 0.00165
(Table 1)
0.00033
0.00132
0.00165
990000
66000'0
(Table 1)
|Fe(SCN)'"laquit.
0.290
0.524
0.803
1.024
1.199
Column F
ISCN aqu
148.6799
135.1678
142.2659 141.8466
134.2843
Average K:140.448](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb39a791-932a-40e9-8866-3329ef2f764e%2F68dd38ef-e9c6-4849-a1be-5ceb9ded4622%2Fuqd711o_processed.jpeg&w=3840&q=75)
The reaction for which equilibrium constant is to be determined is:
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- By the use of Henderson Hasselbalch equation; pH = pKa + log{[acetate ion]/[acetic acid]} 4.5 = 4.75 + log{[0.10 M]/[acetic acid]} -0.25 = log{[0.10 M]/[acetic acid]} [Acetic acid] = 0.10 M/ 10-0.25 [Acetic acid] = 0.10 M/0.56 [Acetic acid] = 0.1786 M Moles of sodium acetate dissolved in 250 mL buffer solution = 0.10 M× (250mL/1000mL) × 1L = 0.025 mol Weight (w) of sodium acetate (purity 100%) dissolved to prepare 250 mL of solution with buffer concentration of 0.10 M is calculate as follow; w100% = 0.025 mol × 82.0343 g/mol = 2.051 g Weight (w) of sodium acetate (purity 99%) is calculate as follow; w99% = 2.051 g× (100/99) = 2.072 g What was the volume of 6.12 M acetic acid HC2H3O2 needed to prepare the 250 mL acetic acid/acetate ion buffer solution required in this part? Show your calculations.What is the retardation factor of a pulse of dissolved benzene move through organic-rich wetland soil (organic carbon fraction of soil, foc=50%) if the effective porosity is 0.4 and the bulk density of the soil is 1.5 g/cm3. Follow these important hints: - Determine organic carbon partition coefficient (Koc) - Use this Equation: K oc = K d / f oc to calculate Kd. Select the range which includes your calculated answer. Group of answer choices 300 to 400 2.0 to 2.5 mg/l 2.0 to 2.5 2.6 to 4.8 0.5 to 1.0 2.6 to 4.8 mg/l None of these ranges include my answer.Solute S has a partition co-efficient of 3.0 between water (Phase 1) and Chloroform (Phase 2). (a) Calculate the concentration of S in chloroform if [S(aq)] is 0.015 M. (b) If the volume of water is 75.0 mL and the volume of chloroform is 15.0 mL, find the quotient (mol S in chloroform)/(mol S in water).
- In the synthesis of hydrocarbons, the carbon source is carbon dioxide. Although the CO2 concentra?on in the atmosphere raises at a drama?c speed, point sources are probably the easier sources for a PtX process. Iden?fy 3 possible point sources, explain why CO2 is formed and what challenges each of the three CO2 streams presentsI need the theoretical molar extinction coefficient of paranitrophenol in mol^-1cm^-1 (using moles not μM). I have to calculate the % difference.At the experimental level it was 7,200 mol^-1cm^-1For the 2° reaction H2(g) + I2(g) → 2HI(g) at 650 K, the collisional cross section, sigma H2-I2, is 0.36 nm2, the reducedmass is 3.32 × 10−27 kg, and the activation energy is 171 kJ mol−1. Use collision theory to calculate the rateconstant. If the actual value of the rate constant is 8.4 × 10−6 M-1s-1, determine the steric factor for this reaction.
- Calculate delt g for Pbl2(s) + Pb2+(aq) +2I-(aq) T= 25C Kp= 8.7x10-9If 5 µM enzyme was used to obtain the data in the summary plot below, V-max = ________________ µM sec-1 and Km = ____________ µM for this enzyme (Enter numeric values to the nearest integer; Do NOT write units.)Choices for slope: a. -1.35 x 10^4 b. 1.35 x 10^4 c. -1.09 x 10^4 d. 1.09 x 10^4 choices for y intercept: a. -27.8 b. 27.8 c. 37.4 d. -37.4 choices for pearson: a. -0.962 b. -1000 c. -0.982 activation energy a. 9.06 x 10^4 b. 113 c. 90.65 collision frequency factor A a. 1.15 x 10^12 b. 113 c. 90.65
- What is ΔHsys for a reaction at 16.9 °C with ΔSsurr = -159 J mol-1 K-1 ? Express your answer in kJ mol-1 to at least two significant figures. (Please type answer no write by hend)Assume no acid-base catalysis occurs and the following data: Under biological conditions (310 K) 1. dGb = -20.00 kJ/mol. 2. The dG of E +S binding to ES (dGs) is -3.00 kJ/mol. 3. dGd mismatch of energy in ES = +2.00 kJ/mol. What is the catalytic power (kcat/k_uncat) at 360 K? Use 1 decimal place.please help this is my 4th time posting this and i havent gotten a correct answer. Please actually draw the graph out. A newly discovered enzyme, MBCase, cleaves carbon-carbon bonds of vicinal alcohol; The kinetic parameters were measured for 1.0 nM Of MBGase and determined to be a Km = 10 nM and a kcat = 100 s-1 a.) Sketch the graph out as a double-reciprocal plot (Lineweaver-Burke Plot) and label: -the axes (with units) -the point on the curve that can be used to determine Km -the point on the curve that can be used to determine Vmax