eger using Integer.parseInt. In case of an exception (when converting the string to an integer), the program must (1) print the corresponding stack trace (printStackTrace) and (2) reset the Scanner object. • The program must catch division by zero exceptions and print a corresponding message in case one occurs. The error should not be printed if the user intends to exit. • The sample input/output is given below for your reference: Give me an int numerator: 0 Give me an int denominator: 1 The quotient is: 0
Write a Java program that repeatedly accepts two integers from the keyboard and prints the quotient to
the console. Your code must adhere to the follow specifications:
• The user must enter 0 for both the numerator and denominator to exit the program.
• You must read the input values using the Scanner’s next() method and then convert to a
primitive integer using Integer.parseInt. In case of an exception (when converting the
string to an integer), the program must (1) print the corresponding stack trace
(printStackTrace) and (2) reset the Scanner object.
• The program must catch division by zero exceptions and print a corresponding message in case
one occurs. The error should not be printed if the user intends to exit.
• The sample input/output is given below for your reference:
Give me an int numerator: 0
Give me an int denominator: 1
The quotient is: 0
Give me an int numerator: 1
Give me an int denominator: 0
An exception occurred. See below for more info:
java.lang.ArithmeticException: / by zero
at DemoClass.main(DemoClass.java:20)
Give me an int numerator: 4
Give me an int denominator: 2
The quotient is: 2
Give me an int numerator: 2
Give me an int denominator: 4
The quotient is: 0
Give me an int numerator: 2
Give me an int denominator: two
An exception occurred. See below for more info:
java.lang.NumberFormatException: For input string: "two"
at
java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:68)
at java.base/java.lang.Integer.parseInt(Integer.java:652)
at java.base/java.lang.Integer.parseInt(Integer.java:770)
at DemoClass.main(DemoClass.java:16)
Give me an int numerator: two
An exception occurred. See below for more info:
java.lang.NumberFormatException: For input string: "two"
at
java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:68)
at java.base/java.lang.Integer.parseInt(Integer.java:652)
at java.base/java.lang.Integer.parseInt(Integer.java:770)
at DemoClass.main(DemoClass.java:13)
Give me an int numerator: 0
Give me an int denominator: 0
Program over!
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