EXPERIMENT 2: Preparation of ca 0.1 mol.dm HCI Solution Pre-calculation: mHC-solaton = 1,16 x 103 x 32 = 3,712 x 102 g 100 !3! CHCL = 3,712 x 102 36,46 x 1dm3 %3D = 10,18 mol.dm 3 CV = C2V2 0,1 mol.dm3 x 500 mL 10,18 mol.dm3 %3D HCI-solution = 4,9 mL %3D C1 Task: Calculate the volume of the same concentrated HCl as from the above experiment which can be diluted to 1000 cm to make a 0.05 mol.dm HCl solution at room temperature.
EXPERIMENT 2: Preparation of ca 0.1 mol.dm HCI Solution Pre-calculation: mHC-solaton = 1,16 x 103 x 32 = 3,712 x 102 g 100 !3! CHCL = 3,712 x 102 36,46 x 1dm3 %3D = 10,18 mol.dm 3 CV = C2V2 0,1 mol.dm3 x 500 mL 10,18 mol.dm3 %3D HCI-solution = 4,9 mL %3D C1 Task: Calculate the volume of the same concentrated HCl as from the above experiment which can be diluted to 1000 cm to make a 0.05 mol.dm HCl solution at room temperature.
Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.108E
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