For each of the molecules or ions in the chart, do the following• Draw the shape predicted by VSEPR theory•Name the shape•Draw a vector (positive tail to negative tip) to indicate the overall dipole of the molecule (if any)Molecule/Ion DrawingName of shapeDirection of dipole (ifany)FNOCO3²-CH3F

For CO32-, it has no dipole moment, because all Oxygen atoms are pulling electron density towards…

Answered: For each of the molecules or ions in…

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter3: Atomic Shells And Classical Models Of Chemical Bonding

Section: Chapter Questions

Problem 59P

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Similar questions

Describe the shapes and compare the polarities of HF and HBr molecules. In each case, identify the end of the molecule that is more positive.
Use the simulation (http://openstaxcollege.org/l/16MolecPolarity) to perform the following exercises for a real molecule. You may need to rotate the molecules in three dimensions to see certain dipoles. (a) Sketch the bond dipoles and molecular dipole (if any) for O3 Explain your observations. (b) Look at the bond dipoles for NH3. Use these dipoles to predict whether N or H is more electronegative. (c) Predict whether there should be a molecular dipole for NH3 and, if so, in which direction it will point. Check the molecular dipole box to test your hypothesis.
Hydrogen azide (also known as hydrazoic acid), HN3, is a covalent molecule in which the hydrogen atom (as a proton) is bonded to a nitrogen atom at one end of the azide ion (see previous problem). Draw the dominant resonance formula or formulas for this molecule. Describe the hybridization about the nitrogen atom to which the hydrogen atom is bonded in the dominant formula or formulas. Use valence bond theory to describe the bonding about this nitrogen atom.
Why do polar molecules have a greater tendency to remain a liquid or a solid at room temperature?
Use the Molecule Shape simulator (http://openstaxcollege.org/l/16MolecShape) to explore real molecules. On the Real Molecules tab, select model mode and S2O. What is the model bond angle? Explain whether the real bond angle should be larger or smaller than the ideal model angle.
In the gas phase, tin (II) chloride is a covalently bonded compound. The number of valence electrons contributed by the tin atom is what you expect from its group in the periodic table. Draw the Lewis diagram for tin (II) chloride, state its electron-pair and molecular geometries, and construct a three-dimensional sketch of the molecule.
Explain whether the following molecules are polar or nonpolar, using VSEPR theory: SF, and NH].
Classify each of the following molecules as polar or nonpolar. H2O2, CF4, N2H2, NO2
Consider the hypothetical molecule PHFBr, in which the phosphorus atom is in the center.This molecule has exactly one central atom. c) According to VSEPR Theory, the molecular geometry is: ___________________d) Is the P-F bond ionic, polar covalent, or nonpolar covalent? How did you decide?e) Do you expect the PHFBr molecule to be polar or nonpolar? Justify your answer.f) Which of the following intermolecular forces should be considered between PHFBrmolecules: Dipole-dipole force, ion-dipole force, London Dispersion Force, or Hydrogenbonding? List all the forces that are appropriate below.
Select ALL of the following that can be used to explain the polarities of NO2 and SeCl42- (these molecules are mentioned in earlier questions). NO2 has a permanent dipole moment or a net dipole moment greater than zero whereas SeCl42- has no net or zero dipole moment. Both molecules are symmetrical and hence nonpolar Due to their respective shapes, in NO2 the bond dipole moments reinforce each other whereas in SeCl42- they cancel out each other. NO2 has no net dipole moment and SeCl42- has a net dipole moment greater than zero. NO2 is an unsymmetrical molecule whereas SeCl42- is a symmetrical ion.

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