For the equation below at equilibrium, what is the shift in the equilibrium position upon adding sodium acetate to the equilibrium mixture of acetic acid and methyl orange, where HMO represents the protonated (acid) form of the indicator and MO- represents the deprotonated (or base) form of the indicator. What is the resulting color of the solution? HMO(aq) + H,O(1) H,O-(aq) + MO(aq) O to the left/red O to the right/yellow O to the left/yellow to the right/red

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter16: Solubility And Precipitation Equilibria
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For the equation below at equilibrium, what is the shift in the equilibrium position
upon adding sodium acetate to the equilibrium mixture of acetic acid and methyl
orange, where HMO represents the protonated (acid) form of the indicator and
MO- represents the deprotonated (or base) form of the indicator. What is the
resulting color of the solution?
HMO(aq)
+ H,O(1) = H.O-(aq) + M0(aq)
O to the left/red
O to the right/yellow
O to the left/yellow
O to the right/red
For the equation below at equilibrium what is the shift in the eguilibrium nonitir
Transcribed Image Text:For the equation below at equilibrium, what is the shift in the equilibrium position upon adding sodium acetate to the equilibrium mixture of acetic acid and methyl orange, where HMO represents the protonated (acid) form of the indicator and MO- represents the deprotonated (or base) form of the indicator. What is the resulting color of the solution? HMO(aq) + H,O(1) = H.O-(aq) + M0(aq) O to the left/red O to the right/yellow O to the left/yellow O to the right/red For the equation below at equilibrium what is the shift in the eguilibrium nonitir
Describe the preparation of a 500. mL of 2.50 M solution cupric sulfate
pentahydrate, starting from the solid reagent? The molecular weight is 249.68
g/mol.
Weigh out 312 grams of the solid reagent and transfer it to a clean and dry flask. Add
O water just enough to dissolve the solid and then add water until the total volume of
the solution is 500. mL
Weigh out 312 x 105 grams of the solid reagent and transfer it to a clean and dry flask.
Add water just enough to dissolve the solid and then add water to mark.
Weigh out 3.12 grams of the solid reagent and transfer it to a clean and dry flask. Add
O water just enough to dissolve the solid and then add water until the total volume of
the solution is 500. mL.
Measure out 312 mL of the reagent and transfer it to a clean and dry flask. Add water
until the final volume of the solution is 500. mL.
Describe the preparation of a 45.0 mL of 0.500 M solution of potassium
permanganate solution, starting from 1.75 M of potassium permanganate
solution?
Dilute 1.75 mL of 1.75 M of potassium permanganate solution to 45.0 mL.
Dilute 12.9 mL of 1.75 M of potassium permanganate solution to 45.0 mL.
Dilute 45.0 mL of 1.75 M potassium permanganate solution and dilute to 0.500 L
mark.
Dilute 12.9 mL of 1.75 M potassium permanganate solution and dilute to 0.500 L
mark.
Transcribed Image Text:Describe the preparation of a 500. mL of 2.50 M solution cupric sulfate pentahydrate, starting from the solid reagent? The molecular weight is 249.68 g/mol. Weigh out 312 grams of the solid reagent and transfer it to a clean and dry flask. Add O water just enough to dissolve the solid and then add water until the total volume of the solution is 500. mL Weigh out 312 x 105 grams of the solid reagent and transfer it to a clean and dry flask. Add water just enough to dissolve the solid and then add water to mark. Weigh out 3.12 grams of the solid reagent and transfer it to a clean and dry flask. Add O water just enough to dissolve the solid and then add water until the total volume of the solution is 500. mL. Measure out 312 mL of the reagent and transfer it to a clean and dry flask. Add water until the final volume of the solution is 500. mL. Describe the preparation of a 45.0 mL of 0.500 M solution of potassium permanganate solution, starting from 1.75 M of potassium permanganate solution? Dilute 1.75 mL of 1.75 M of potassium permanganate solution to 45.0 mL. Dilute 12.9 mL of 1.75 M of potassium permanganate solution to 45.0 mL. Dilute 45.0 mL of 1.75 M potassium permanganate solution and dilute to 0.500 L mark. Dilute 12.9 mL of 1.75 M potassium permanganate solution and dilute to 0.500 L mark.
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