Given an array of elements drawn from a totally ordered set. Present an O(n)-time algorithm that either returns an element that appears at least ||n times in the list or reports that no such an element exists. [Hint: Use Algorithm Select]

Given an integer array A[1..n] you are to list the k smallest elements. What method will you use when (i)k=0(1) Explain why you chose the algorithm you chose for parts (i)

write a python program to find the" kth smallest element" in the ascending order sorted list. also check if the given number is present in the list using any searching technique is suppose element to be searched is not available then display "not present" otherwise display" present"

DO NOT COPY FROM OTHER WEBSITES COrrect and detailed answer will be Upvoted else downvoted. Thank you!

Given a Sorted Array of integers containing duplicates. Find the frequency of every unique element present in the array. Frequency is defined as the number of occurrence of any element in the array. Solve in Java

Consider this alogrithm:// pre: array A of length n, each A[i] is picked randomly uniformly// from the set {0,1,2,3,4,5,6,7,8,9}.// post: return the index of the first occurrence of "check digit" of A// (already computed in the code)// return -1 if check digit is not foundint FindCheckDigit(A) {check_digit = 0for (i=0; i < n; i++)     check_digit = check_digit + A[i]check_digit = check_digit % 10 # % means remainder of divisionfor (i = 0; i < n; i++) {     if (A[i] == check_digit) {          return i     }}return -1;}Compute the average runtime for this algorithm. Show all details of your computation for both loops.

Given a sorted array of size N and an integer K, find the position at which K is present in the array using binary search. Example 1: Input: N = 5 arr[] = {1 2 3 4 5} K = 4 Output: 3 Explanation: 4 appears at index 3.

Given an ordered list, what is the Big-O of finding the smallest element in the list?

There are two n-element arrays A and B the task is to permute them such that A[i]+b[i]>=k Can someone walk me through the code. I dont understand the iList and jList and why we have if j and i not in List we do List.append. Also at the end why we do if len(iList)+len(jList)==len(A)+len(B) ? def twoArrays (k, A, B): A.sort() B. sort() iList = [] jList = [] for i in range (len (A)): for j in range (len (B)): if(A[i]+B[j]>=k): if j not in jList and i not in iList: iList.append(i) jList.append(j) print (iList) print (jList) if(len (iList) + len(jList) ==len (A) + len(B)) return "YES" else: return "NO"

an array of integers nums sorted in ascending order, find the startingand ending position of a given target value. If the target is not found in thearray, return [-1, -1]. For example:Input: nums = [5,7,7,8,8,8,10], target = 8Output: [3,5]Input: nums = [5,7,7,8,8,8,10], target = 11Output: [-1,-1].