Given an JavaScript object list of books that each have a pages attribute to define the number of pages in the book, find the sum of all the pages in the object list of books using recursion. Keep in mind: The input list object may be completely empty (ex. {}) The next attribute may not be defined function getPageCount(list) { // your code here // returns an integer } Example test case: Input: { "book":"A", "pages":1, "next":{ "book":"B", "pages":2, "next":{ "book":"C", "pages":3, "next": null } } } Output: 6 Reasoning: 1 + 2 + 3 pages

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Count word dominators def count_word_dominators(words): If you already solved the earlier count_dominators problem, you might notice that even though the problem was originally stated for lists of integers, the logic of domination did not depend on this fact in any way. As long as the individual elements can be compared with each other for order, the Pythonic spirit of duck typing allows the very same count_dominators function to handle a list of strings just as smoothly as it would handle a list of integers! For example, the function call count_dominators(['dog','emu','cat','bee']) would return 3, since 'emu', 'cat'and 'bee' dominate all words coming after them in the list when using the lexicographic order comparison. If your count_dominators function does not already pass this hurdle, try to rewrite it to contain no baked-in assumptions about elements being specifically integers. However, things become more interesting if we define domination between words of equal length with a…

1. Divisors: In a class Divisors.java, read in a maximum integer n and use nested loops to print a list of divisors for each of 1 through n as shown in the following transcript. Sample transcript (input underlined): Largest integer? 100 1: 1 2: 1 2 3: 1 3 4: 1 2 4 95: 1 5 19 95 96: 1 2 3 4 6 8 12 16 24 32 48 96 97: 1 97 98: 1 2 7 14 49 98 99: 1 3 9 11 33 99 100: 1 2 4 5 10 20 25 50 100