Given the following code segment with the enhanced for loop: int [] numbers = {6, 8, 9, 5}; for (int val : numbers) System.out.print(val + “ “);  i)  What would be the value of numbers[1] after the above code is executed?    __________ ii)  What would be the value of numbers[4] after the above code is executed?    __________

Language is C++  Lab10B: Binary Bubbles. Binary search is a very fast searching algorithm, however it requires a set of numbers to be sorted first. For this lab, create an array full of 11 integers which the user will generate. Like in the previous lab, assume that the values will be between -100 and +100. Then, using the sorting algorithm called BubbleSort, put the array in the correct order (from lowest to highest number). After this, please printthe array to the screen. Finally, search the array for the target value using Binary Search.The BinarySearch code will implement the algorithm described in the lecture slides. During this, you should print out a few key values which help Binary Search function. For example, this algorithm focuses on a low, mid, and high which correspond to the indices in the array the algorithm is currently considering and searching. Printing these values during the search process will help with debugging and fixing any issues. • BubbleSort sorts the array…

Please help guide me in the direction what I am doing wrong. I am in the process of the code but it reached an error please guide me where I need to change before I continue the rest of the code. That is why it will be incomplete   #include "stdafx.h"#include <iostream> #include <limits>#include <cstdlib>#include <array>#include <ctime>#include <string>#include <vector>#include <cctype>#include <iterator>#include <algorithm>#include <cmath>#include<windows.h>#include <conio.h>   using namespace std; double donationamount[50];string fullname[50];int departmentdonation[50]; struct donorinfo{ vector<string>donor_name[50];vector<double>donor_amount[50];vector<double>department_donation[50];} dvariable;   void inputdonor(donorinfo *);void displaydonor(donorinfo *);void editdonor(donorinfo *);void displayorganization(donorinfo *); int main(){ int index; donorinfo Donors[50]; int choice;const int…

C++ . Please make sure code has "Enter integer 1, etc" instead of allowing you to type integers without prompt.

#include<stdio.h>#include<string.h>struct info{char names[100];int age;float wage;};int main(int argc, char* argv[]) {int line_count = 0;int index, i;struct info hr[10];if (argc != 2)printf("Invalid user_input!\n");else {FILE* contents = fopen (argv[1], "r");struct info in;if (contents != NULL) {printf("File has been opened successfully.\n\n");while (fscanf(contents, "%s %d %f\n",hr[line_count].names, &hr[line_count].age, &hr[line_count].wage) != EOF) {printf("%s %d %f\n", hr[line_count].names, hr[line_count].age, hr[line_count].wage);line_count++;}printf("\nTotal number of lines in document are: %d\n\n", line_count);fclose(contents);printf("Please enter a name: ");char user_input[100];fgets(user_input, 30, stdin);user_input[strlen(user_input)-1] = '\0';index = -1;for(i = 0; i < line_count; i++){if(strcmp(hr[i].names, user_input) == 0){index = i;break;}}if(index == -1)printf("Name %s not found\n", user_input);else{while(fread(&in, sizeof(struct info), 1,…

Problem Description - JAVA PROGRAMMING Use a Two-dimensional (3x3) array to solve the following problem: Write an application that inputs nine numbers, each of which is between 1 and 10, inclusive.  Display the array after the user inputs each value. Rotate/flip the array by changing places. Make the rows columns and vice versa. You have to move the elements to their new locations.   Remember to validate the input and display an error message if the user inputs invalid data.  Documentation and the screenshot(s) of the results.  Example:  1  2  3 4  5  6 7  8  9 the result will be :  1  4  7 2  5  8 3  6  9

Write a while loop to read positive integers from input until a non-positive integer is read. For each positive integer read before the non-positive integer, add the positive integer plus five to vector vect1. Ex: If the input is 9 1 2 8 -999, then the output is: 14 6 7 13 Note: Positive integers are greater than 0. 1 #include 2 #include 3 using namespace std; 4 5 int main() { 6 7 8 9 10 11 12 13 14 15 16 17 } vector vect1; int value; int i; V* Your code goes here */ for (i = 0; i < vect1.size(); ++i) { cout << vect1.at (i) << endl; } return 0; I

C++   I am lost, can you help me find my way please   Finding values in vectors.   Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 2, 1, 2} and matchValue is 2 , then numMatches should be 3.Your code will be tested with the following values:* matchValue: 2, userValues: {2, 2, 1, 2} (as in the example program above)* matchValue: 0, userValues: {0, 0, 0, 0}* matchValue: 50, userValues: {10, 20, 30, 40} #include <iostream>#include <vector>using namespace std; int main() {   const int NUM_VALS = 4;   int matchValue;   unsigned int i;   int numMatches = -99; // Assign numMatches with 0 before your for loop   vector<int> userValues(NUM_VALS);    cin >> matchValue;    for (i = 0; i < userValues.size(); ++i) {      cin >> userValues.at(i);   }      cin >> numMatches;   numMatches = userVals.at(0);   for (i = 0; i < userVals.size(); ++i) {      if…

I need to write a program named Search.java that uses a function called search_string to check whether a string exists in the array or not. 1- The array of strings is iterated using a for loop and the value at every index is compared with the value to be searched in the array. 2- A boolean variable is set if any array value matches with the string. 3- At the end of the loop, this boolean variable is checked to determine if the array contains the string. It may be necessary to import java.util.Arrays then use Arrays.toString, String equals(). Output should be as picture shows