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- Rank the set of substituents below in order of priority according to the Cahn-Ingold-Prelog sequence rules.1 = highest priority.(a) -ch3 (b) -br (c) -h (d) -iRank the following sets of substituents according to the Cahn-Ingold-Prelog sequence rules.Which group is of lower priority than –CH=CH2 according to Cahn-Ingold-Prelog rules. –CH=C(CH3)2 –C(CH3)3 –CH(CH3)2 –CH=CHCl a b c d
- Which of the following groups has the highest priority according to the Cahn-Ingold-Prelog sequence rules? a. CH2Cl b. CHO c. CH2OH d. CH3A)Circle all of the stereo centers in MDMA. B) assign the absolute stereochemistry (R or S) for each stereo centerRank the following groups in order of decreasing priority. −CH=CH2, −CH3, −C≡CH, −H
- Using Cahn-Ingold-Prelog rules, rank these substituents from highest priority to lowest priority. A) III > I > II B) II > I > III C) III > II > I D) I > II > III E) II > III > I1. How can the chirality of compound 1? 2. How the configuration inversion of -OH moiety of compound 2 occur stereoselectively? Thank you....Arrange the following group in order of increasing priority. Q) -OCH3 -CH(CH3)2 -B(CH2CH3)2 -H
- Which of the following represents the correct Cahn-Ingold-Prelog priority ranking of C5H11 substituents (used to determine R/S configuration) from lowest to highest? A) CH3(CH2)4– B) (CH3)3CCH2– C) C3H7CH(CH3)– D) (CH3)2CHCH2CH2–Hexahelicene seems a poor candidate for optical activity because all its carbon atomsare sp2hybrids and presumably flat. Nevertheless, hexahelicene has been synthesized and separated into enantiomers. Its optical rotation is enormous: [a]D = 3700°.Explain why hexahelicene is optically active, and speculate as to why the rotation isso largeUsing the Cahn-Prelog-Ingold priority rules for ranking substituents around a chirality center, which of the following groups has the highest priority?a.) -CO2Hb.) -CO2CH3c.) -CH2OHd.) -OH