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With following Binary Node and Binary Tree class need help making an AVL Tree with the Insert and Remove Functions that deals with the rotations. Use inheritance from Binary Tree to create AVL Tree. Modifications to the Binary Node or Binary Tree are fine.
Trees should be specific for strings
Binary Node Class:
public class BinNode
{
private String data;
private BinNode left;
private BinNode right;
public BinNode(){
data = "";
left = null;
right = null;
}
public BinNode(String d){
data = d;
left = null;
right = null;
}
public void setData(String d){
this.data = d;
}
public String getData(){
return this.data;
}
public void setLeft(BinNode l){
this.left = l;
}
public BinNode getLeft(){
return this.left;
}
public void setRight(BinNode r){
this.right = r;
}
public BinNode getRight(){
return this.right;
}
}
Binary Tree Code:
public class BinaryTree
{
private BinNode root;
private BinNode curr;
/* Function to traverse right */
public void goRight() {
this.curr = this.curr.getRight();
}
public BinaryTree()
{
root = new BinNode();
curr = new BinNode();
}
public BinNode getRoot(){
return this.root;
}
/* Function to check if tree is empty */
public boolean isEmpty()
{
return this.root == null;
}
/* Functions to insert data */
public void insert(String data)
{
this.root = insert(this.root, data);
} //done
/* Function to insert data recursively */
private BinNode insert(BinNode node, String data)
{
if (node == null)
node = new BinNode(data);
else
{
int i = node.getData().compareTo(data);
if (i < 0) {
// Go right
node.setRight(insert(node.getRight(), data));
} else if (i >= 0) {
// Go left
node.setLeft(insert(node.getLeft(), data));
}
// write this!
}
return node;
}
/* Function to count number of nodes */
public int countNodes()
{
return countNodes(this.root);
}
/* Function to count number of nodes recursively */
private int countNodes(BinNode r)
{
if (r == null) {
return 0; // If the current node is null, there are no nodes to count.
}
int leftCount = countNodes(r.getLeft()); // Count nodes in the left subtree
int rightCount = countNodes(r.getRight()); // Count nodes in the right subtree
// Add 1 to count the current node itself
return 1 + leftCount + rightCount;
}
/* Function to search for an element */
public BinNode search(String val)
{
return search(this.root, val);
}
/* Function to search for an element recursively */
private BinNode search(BinNode r, String val)
{
// Base case: If the current node is null, the value is not found.
if (r == null) {
return null;
}
int comparison = val.compareTo(r.getData());
if (comparison < 0) {
// Value is smaller, so search in the left subtree.
return search(r.getLeft(), val);
} else if (comparison > 0) {
// Value is larger, so search in the right subtree.
return search(r.getRight(), val);
} else {
// Value is equal to the current node's data, so it's found.
//this.curr = r;
return r;
}
}
/* Function for inorder traversal */
public void inorder()
{
inorder(this.root);
}
private void inorder(BinNode r)
{
if (r != null)
{
inorder(r.getLeft());
System.out.print(r.getData() +" ");
inorder(r.getRight());
}
}
/* Function for preorder traversal */
public void preorder()
{
preorder(root);
}
private void preorder(BinNode r)
{
if (r != null)
{
System.out.print(r.getData() +" ");
preorder(r.getLeft());
preorder(r.getRight());
}
}
/* Function for postorder traversal */
public void postorder()
{
postorder(root);
}
private void postorder(BinNode r)
{
if (r != null)
{
postorder(r.getLeft());
postorder(r.getRight());
System.out.print(r.getData() +" ");
}
}
// find the in-order successor of a given node
public BinNode findInorderSuccessor(BinNode node) {
BinNode current = node.getRight();
while (current.getLeft() != null) {
current = current.getLeft();
}
return current;
}
//Remove function
public void remove(String key) {
// Find the node to be removed and its parent
BinNode parent = null;
BinNode n = this.root;
while (n != null && !n.getData().equals(key)) {
parent = n;
if (key.compareTo(n.getData()) < 0) {
n = n.getLeft();
} else {
n = n.getRight();
}
}
if (n == null) {
// Key not found, nothing to remove
return;
}
// Case 1: Node with no children
if (n.getLeft() == null && n.getRight() == null) {
if (parent == null) {
// Removing the root node
this.root = null;
} else if (parent.getLeft() == n) {
parent.setLeft(null);
} else {
parent.setRight(null);
}
}
// Case 2: Node with one child
else if (n.getLeft() == null || n.getRight() == null) {
BinNode child = (n.getLeft() != null) ? n.getLeft() : n.getRight();
if (n == this.root) {
this.root = child;
} else if (parent.getLeft() == n) {
parent.setLeft(child);
} else {
parent.setRight(child);
}
}
// Case 3: Node with two children
else {
BinNode successor = findInorderSuccessor(n);
n.setData(successor.getData());
remove(successor.getData()); // Recursively remove the successor
}
}
}
you can extend the BinaryTree class to create an AVLTree class, and then modify the insert method to ensure the AVL property is maintained by performing rotations as necessary. Here's a step-by-step guide:
- Create an
AVLTreeclass that extendsBinaryTree:
Modify the insert method in the AVLTree class to ensure AVL balance after insertion. To do this, you'll need to perform appropriate rotations (left or right rotations) when the AVL property is violated. You can do this by tracking the height of the nodes and checking the balance factor.
Step by stepSolved in 3 steps
- Given Class:- import java.util.*; // Iterator, Comparatorpublic class BinarySearchTree<T> implements BSTInterface<T>{protected BSTNode<T> root; // reference to the root of this BSTprotected Comparator<T> comp; // used for all comparisonsprotected boolean found; // used by removepublic BinarySearchTree() // Precondition: T implements Comparable// Creates an empty BST object - uses the natural order of elements.{root = null;comp = new Comparator<T>(){public int compare(T element1, T element2){return ((Comparable)element1).compareTo(element2);}};}public BinarySearchTree(Comparator<T> comp) // Creates an empty BST object - uses Comparator comp for order// of elements.{root = null;this.comp = comp;}public boolean isFull()// Returns false; this link-based BST is never full.{return false;}public boolean isEmpty()// Returns true if this BST is empty; otherwise, returns false.{return (root == null);}public T min()// If this BST is empty, returns null;//…arrow_forward4. Complete the fuction definition given below that takes the root node of a tree as a parameter and returns the count of nodes. int count_nodes(Node *root){ // complete the function }arrow_forwardPlease write the code in C. The screenshot attched provides the template to write in C.arrow_forward
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