Trial 1 Trial 2 1-Mass of empty evaporating dish 55.312 g 55.315 g 56.619 g 56.018 g 56.448 g 2- Mass of evaporating dish + MgSO4.nH2O 3-Mass of evaporating containing the salt after heating 4-Mass of MgS04 (line3 - line1) 55.889 g 5- Moles of MgSO4 6- Mass of nH20 (line2- line3) 7- Moles of H2O 8-n= Mole ratio: moles of H2O/Moles of MgSO4 (line7/ line5) Average value of n ( as a decimal): Rounded average value of n: Formula of Magnesium sulfate hydrate:
Q: Trial 1 0.063g 1. Mass of Mg consumed, g 2. Moles of Mg consumed, n Oml 3. Initial eudiometer…
A: Moles of Mg consumed Mass of Mg consumedAtomic mass of Mg=0.063 g24.3 g/mol=0.00259 mol
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Q: Trial 1 Mass of Sample (g) 0.127 Initial Buret Reading (mL) Final Buret Reading (mL) Volume of KMn04…
A: Moles of KMnO4 delivered till equivalence point = 0.000205 mol The balanced equation for the…
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A: Given: Precipitate: Ba3(PO4)2 molar mass of Ba3(PO4)2 = 601.93 g/mol
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Q: Student Name: Data Trial 1 Trial 2 Mass of flask, rubber band, and foil (g) 143.2 92 143.44 136.91…
A: Please have a look on the solution below:
Q: Trial 1 Trial 2 12.0425 12.042s Mass of KNO3 (g) 9.8585 12,552 Mass of water (g) Solubility (g KNO3/…
A:
Q: Trial 1 Trial 2 Trial 3 Trial 4 Mass of KHC8H4O4 (KHP) 2.0158 KHP 1.9657 KHP 2.0053 KHP 1.9801 KHP…
A: The number of moles of any solute is the ratio of given mass to the molecular mass of the solute.…
Q: Calculations for experimentally determining R Trial 1 Trial 2 Mass of Mg ribbon (g) 0.031 0.039…
A: Trial 1: Given that, Mass of magnesium ribbon =0.031 g Temperature of H2(g) = 24.0 °C Volume of…
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A: The calculation is given below-
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A: Density is defined as mass per unit volume . 1cubic meter has 1000000 ml of volume
Q: 6 Measuring Mass of Monoprotic Unknown Acid Trial 1 Trial 2 Trial 3 8 Mass of unknown acid 10 0.3059…
A: Since this is a monoprotic acid (HA), it will react with 1 NaOH. Balanced equation: HA(aq) +…
Q: Trial 1 Trial 2 Trial 3 0.063g 0.063g 0.065g 1. Mass of Mg consumed, g 2. Moles of Mg consumed, n…
A:
Q: Trial 1 Trial 2 (1) Mass of hydrate 1.215 1.163 by (2) Mass of anhydrous salt 0.914 g. 0.828 (3)…
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Q: Parameters Trial 1 Trial 2 Mass of sample, ml 20 20 Concentration of standard AGNO3 0.06090 0.06090…
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Q: Calculations for experimentally determining R Trial 1 Trial 2 Mass of Mg ribbon (g) 0.033 0.039…
A: Trial 1: Given that, Mass of magnesium ribbon =0.033 g Temperature of H2(g) = 23.5 °C Volume of…
Q: Table 2: Masses of compounds used and observations NaCI CusO+-5H20 (NH4)2Fe(SO4)2 Appearance of…
A: Mass of compounds used: For NaCl = 12.8364 - 11.6023 = 1.2341 gms For CuSO4.5H2O = 12.7398 - 11.4888…
Q: Conc. of NaOH: TRIAL 1 TRIAL 2 TRIAL 3 Mass of flask 81.061 g 69.692 g 96.039 g Mass of flask and…
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Q: Quantity Trial 1 Trial 2 Trial 3 MNAOH (exact concentration) 1.189 1.189 1.189 Vinitial buret…
A: Note : Since you have asked multiple question, we will solve the first question for you. If youwant…
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A:
Q: DATA/CALCULATION SHEET NAME 1. crucible, cover, BaCl2 2H2O \$,2061 crucible and cover 14.0188g BaCl2…
A:
Q: DATA DESCRIPTION TRIAL 1 TRIAL 2 Mass of Empty Evaporating Dish 35.6450g 35.6452g Mass of…
A: Mass of the kernel can be calculated as
Q: Report Sheet Table 3.1. Trial 1 Trial 2 Trial 3 Mass of watch glass and sample 49.322 50.니0 90.191…
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Q: Standardization Data Table Trial 1 Trial 2 Trial 3 Mass KHP, g .422 .390 .475 Final Volume, mL 23.20…
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A: Hello, since you had submitted more than three sub-part in a question, so first three sub-parts…
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A: Here I am assuming that the molarity of the standard NaOH solution is 0.125 M. And the Density of…
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Q: Nitrogen N2 (g) 191.6 r answer to the ne N2H4 (g) 95.4 159.4 238.5 N2H4 (I) 50.6 149.3 121.2 NH3 (g)…
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Q: Given the following unbalanced response: NaClO3 + H2O + I2 HIO3 + NaCl 0.25 ml sample of NaClO3…
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Q: Trial-1 Volume of NaOH in Liters. Moles of NaOH (MxV) Moles of CH,COOH Molar Mass Of CH,COOH (g/mol)…
A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…
Q: Conc. of NaOH: TRIAL 1 TRIAL 2 TRIAL 3 Mass of flask 81.061 69.692 96.039 Mass of flask and vinegar…
A: Given
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A: Answer:- This question is answered by using the simple concept of stoichiometry which involves the…
Q: Trial 1 Trial 2 Trial 3 Vinegar Volume (mL) 5.00 5.00 5.00 Final buret reading of NaOH(mL) 34.96…
A: Trial 1 Trial 2 Trial 3 Vinegar Volume (mL) 5.00 5.00 5.00 Final buret reading of NaOH(mL)…
Q: Trial 1 Volume of unknown sulfate 100.0ml Mass of empty crucible and cover 20.4328g Mass of crucible…
A:
Q: 50.0 g solute in 0.425 MK2CO3 Express your answer with the appropriate units. HÁ V = Value Units…
A: Concentration of K2CO3=0.425M Mass of K2CO3 =50.0g
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- An analyst analyse two cans of beer each 5 times to determine the ethanol contents. The first can yielded an average of 4.92% ethanol and the second can an average of 5.12% ethanol. spooled = 0.45% for all 10 analyses. Do the data indicate a statistical difference in ethanol contents between the two cans of beer with 99% confidence? Show all equations.Please answer super fast and answer all questions and show calculations For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466Explain and show work step by step: 1. A mixture of Al2O3(s) and CuO(s) weighing 18.371 mg was heated under H2(g) in a thermogravimetric experiment. On reaching a temperature of 1000 °C, the mass was l7A62 mg and the final products were Al2O3(s), Cu(s), and H20(g). Find the weight percent of Al2O3(s)in the original solid mixture.
- DATA AND CALCULATIONS Reactant: Na2CO3 TEST TUBE A, B, C TRIAL A TRIAL B TRIAL C Mass of test tube and boiling chip 504g__ 17.969g_ 17.800g_ Mass of tube with Na2CO3 861g 18.314g 18.186g Net mass of reactant used __________ __________ __________ Number of moles of reactant __________ __________ __________ Mass of tube with NaCl product 882g 18.332g___ 18.184g___ Mass after repeated heating 18.879g 18.333g____ 18.186g___ Net mass of NaCl product __________ __________ __________ Number of moles of NaCl __________ __________ __________ Ratio of moles NaCl to moles of reactant __________ __________ __________ Average mole-to-mole ratio from your trials _______________A student obtained 2.111 g of a mixture containing four components. After performing separation by chemical and physical methods, the student obtained the following mass data: Component 1: 0.486 g Component 2: 0.317 g Component 3: 0.127 g Component 4: 0.929 g Calculate the total percent recovery of the mixture. (Please show work)a pharmacist added 15 g of 20% w/w calamine cream to 300g of aquaphor. what is the percent stregth w/w of the final calamine product? Show work of how to get the answer. Answer should be 0.95%
- TRIAL I II Weight of the impure benzoic acid 5.1 5.3 Weight of the watch glass + sublimate 133.8 128.7 Weight of the watch glass (empty) 131.5 126.9 Weight of the sublimate Percentage recovery Melting point of benzoic acid °C T1: Temperature when it starts to melt 111.8 121.3 T2: Temperature when it completely melts 133.0 123.4 Calculate the percentage recovery/yield for each trial. Determine the average percentage recovery/yield.Calculate the Constant Weight (in grams) of the Empty Crucibles. Show your solution. Crucible No. 1 2 3 Weighing 1 22.6035 22.0223 24.1535 Weighing 2 22.6017 22.0204 24.1533 Weighing 3 22.5994 22.0199 - Weighing 4 22.5992 - - Constant Weight, g ??? ??? ???Show ALL calculations pls. Don't reject if you dont know how to answer I need this. a. What are the average values for vph and vmo? Include calculation of net volume and errorsb. What is/are the component/s of the soda ash sample? c. Calculate the percent composition of the component/s. No need to include error propagation, but you still need to apply Significant Figure rules.
- Measurement Trial #1 Trial #2 Trial #3 mass of water/calorimeter/lid 82.73g 82.02g 84.46g mass of empty calorimeter & lid: 8.12g 8.16g 8.18g Mass of Water 74.61g 73.86g 76.28g Tf of water (in calorimeter) 26.8c 26.1c 26.4c Ti of distilled water: 20.6c 20.4c 20.3c ΔT water 5.48c 5.7c 6.1c Determine the amount of heat transferred from the metal cylinder to the water in the calorimeter for each trial using the equation below. The change in temperature used for this calculation is the change in temperature of the water (ΔTwater). Show your work. Do not round your answers for these calculations. qwater = mwater ´ Cp of water ´ ΔT watercan you answer, please? the experimental data are Reference: https://www.youtube.com/watch?v=OOXRkycKEOc&feature=youtu.be and https://www.youtube.com/watch?v=3wLJLm0QLpg&feature=youtu.beH2SO3 = 0.2556 M, Ka1 = 1.6 x 10-2 , Ka2 = 6.4 x 10-8 NaOH = 0.3106 M please show all work all information needed is here