How many grams of barium phosphate (601.9 g/mol) can be produced when 6.0g of barium nitrate (261.3 g/mol) reacts with an excess of hydrochloric acid according to the following reaction? * 3Ba(NO3)2 + 2H3PO, → Ba,(PO4)2 + 6HNO3 O 0.87 g O 4.6 g O 7.8 g O 41 g Vhich change woul action

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Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.19PAE: 4.19 How many metric tons of carbon are required to react with 7.83 metric tons of Fe2O3 according...
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How many grams of barium phosphate (601.9 g/mol) can be produced
when 6.0g of barium nitrate (261.3 g/mol) reacts with an excess of
hydrochloric acid according to the following reaction? *
3Ba(NO)2 + 2H PO, →
Ba
,(PO4)2 + 6HNO3
6ΗΝΟ,
->
2
4.
O 0.87 g
O 4.6 g
O 7.8 g
O 41 g
Which change wou
reaction
Transcribed Image Text:How many grams of barium phosphate (601.9 g/mol) can be produced when 6.0g of barium nitrate (261.3 g/mol) reacts with an excess of hydrochloric acid according to the following reaction? * 3Ba(NO)2 + 2H PO, → Ba ,(PO4)2 + 6HNO3 6ΗΝΟ, -> 2 4. O 0.87 g O 4.6 g O 7.8 g O 41 g Which change wou reaction
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