How many moles of H2SO, are required to completely react with 7.20 mol of Al according to the balanced chemical reaction: 2 Al(s) + 3 H2SO.(aq) Al2(SO.)3(aq) + 3 H2(g) 7.20 mol Al mol H,SO, STARTING AMOUNT

World of Chemistry, 3rd edition
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ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Chapter9: Chemical Quantities
Section: Chapter Questions
Problem 56A
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How many moles of H2SO, are required to completely react with 7.20 mol of Al
according to the balanced chemical reaction:
H2(g)
Al(s) + 3
H2SO«(aq) → Al2(SO4);(aq) +
2
mol H2SO4
7.20
mol Al
STARTING AMOUNT
7.20 mol Al
= mol H2SO4
RESET
DELETE
ANSWER
ADD FACTOR
*( )
%3D
26.98
98.08
7.20
342.14
1
2.40
21.6
3.60
6.022 x 1023
2.02
10.8
mol Al
g H2
g Al
mol Al2(SO4)3 g H2SO4
mol H2
mol H2SO4
g Al2(SO4)3
Transcribed Image Text:How many moles of H2SO, are required to completely react with 7.20 mol of Al according to the balanced chemical reaction: H2(g) Al(s) + 3 H2SO«(aq) → Al2(SO4);(aq) + 2 mol H2SO4 7.20 mol Al STARTING AMOUNT 7.20 mol Al = mol H2SO4 RESET DELETE ANSWER ADD FACTOR *( ) %3D 26.98 98.08 7.20 342.14 1 2.40 21.6 3.60 6.022 x 1023 2.02 10.8 mol Al g H2 g Al mol Al2(SO4)3 g H2SO4 mol H2 mol H2SO4 g Al2(SO4)3
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