If 1.00 molmol of argon is placed in a 0.500-LL container at 18.0 ∘C∘C , what is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation)? For argon, a=1.345(L2⋅atm)/mol2a=1.345(L2⋅atm)/mol2 and b=0.03219L/molb=0.03219L/mol.
If 1.00 molmol of argon is placed in a 0.500-LL container at 18.0 ∘C∘C , what is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation)? For argon, a=1.345(L2⋅atm)/mol2a=1.345(L2⋅atm)/mol2 and b=0.03219L/molb=0.03219L/mol.
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter6: The Gaseous State
Section: Chapter Questions
Problem 6.10QE
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If 1.00 molmol of argon is placed in a 0.500-LL container at 18.0 ∘C∘C , what is the difference between the ideal pressure (as predicted by the
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