Implement a priority queue using Python. Please follow the functions’ pseudo-code from the textbook and write a few testings in the “main” function.

In Kotlin, Write a recursive function called myZip, with an expression body. MyZip takes two Lists and returns a List of Pairs in which each value may be any type (I suggest your start by thinking out how to represent this data type). The pairs consist of corresponding elements in the two lists (the first element of the first list and the first element of the second list, etc). The base case should be that either (or both) of the original lists has length 1, so that, if the lists have different length, the zipping stops when the first list runs out of values.

Write the code in python to define the function has_adjacent_repeats(mystr), which takes a string parameter and returns a boolean result.   - If mystr has at least one instance of adjacent characters being equal, return True   - Otherwise, return False Hint: You can iterate over the positive indices i for characters in mystr: 1, 2, 3, ...., len(mystr)-1 with a for loop. For each i, if the character at index i matches the character at index i - 1, return True. Otherwise, if no doubled character is found in the entire string, return False. For example: Test Result if not (has_adjacent_repeats("NOODLES") is True): print("error")   if not (has_adjacent_repeats("Bananas") is False): print("shwoopsie")   if not (has_adjacent_repeats("Hanoverr") is True): print("error")

python help... Write a function justVowels() that takes a string as a parameter and returns a new string that contains all the vowels found in the parameter string. The vowels in the returned string should appear in the same order as they did in the parameter string. A vowel is one of a, e, i, o, or u. both the upper- and lower-case vowels should be included. The characters in the returned string should have the same capitalization as they did in the parameter string. If the function is given a string without any vowels or an empty string, it should return the empty string. Use the if-else condition with iterate loop pattern. Don’t forget to include the docstring and comments.    How it should run... >>> justVowels('Did you include your collaboration statement') 'iouiueouoaoaioaee' >>> justVowels('If you did not include your collaboration statement no points') 'Iouioiueouoaoaioaeeooi' >>> justVowels('1,2,3,4,...') '' >>> justVowels('') ''

PHP Write a wordFilter function Write a function wordFilter($str) that takes a string representing a sentence as a parameter. It should replace all occurrences of certain blacklisted words with asterisks of the same length and return the substituted sentence. The words “shoot” “darn” and “fudge” (case insensitive) are considered blacklisted. However, these words as part of a larger word should be left alone (e.g. overshoot is fine as it is). Use one or more regular expressions with replacements in your solutions (e.g. preg_replace).

Write a one sentence description of this function and suggest a more descriptive name. int func1(double x) {return (int)(x + 0.5); }

Write a function mode (numlist) that takes a single argument numlist (a non-empty list of numbers), and returns the sorted list of numbers which appear with the highest frequency in numlist (i.e. the mode, except that we want to be able to deal with the possibility of there being multiple mode values, and hence use a list ... and sort the mode values while we are at it ... obviously). For example: >>> mode ([2, 0, 1, 0, 2]) [0, 2] >>> mode([5, 1, 1, 5, 1]) [1] >>> mode ([4.0]) [4.0]

How to write a function in python where it takes a list of string s. Where s= ["hello","lazyness","polite","politness"]. The function takes the string s as input and returns a string that is the longest even length string that ends with "ness". But if there is no string that ends with "ness" then an empty string is returned.

Implement a function pairsThatSum that accepts two arguments: 1. a target number2. a list of numbers the function then returns a list of tuple s that contains all pairs of numbers from the list that sum to the given target number. Note: the pair can be two numbers with the same value, e.g. (2,2) but these must be different items (have different locations) in the list. See the last example below. each pair should be reported only once (don't include a pair and its reverse), and each pair's values should be listed in the order that they occur in the list. E.g., the first example records the pair (0,3) instead of the pair (3,0) , because 0 occurs in the list before 4 . the list of pairs should be ordered by the order of the first value in the list, e.g., (0,3) comes before (1,2) because 0 comes before 1 in the list. (note: if you take the right approach, you won't have to do anything extra for this requirement)   Below is an example of the output from the code: >>>…

Implement a function findMixedCase in Python that: accepts a single argument, a list of words, and returns the index of the first mixed case word in the list, if one exists, (a word is mixed case if it contains both upper and lower case letters), and returns -1 if the all words are either upper or lower case. sample: >> findMixedCase( ['Hello','how','are','you'] ) # 'Hello' is mixed case0