Write the code in python to define the function has_adjacent_repeats(mystr), which takes a string parameter and returns a boolean result.   - If mystr has at least one instance of adjacent characters being equal, return True   - Otherwise, return False Hint: You can iterate over the positive indices i for characters in mystr: 1, 2, 3, ...., len(mystr)-1 with a for loop. For each i, if the character at index i matches the character at index i - 1, return True. Otherwise, if no doubled character is found in the entire string, return False. For example: Test Result if not (has_adjacent_repeats("NOODLES") is True): print("error")   if not (has_adjacent_repeats("Bananas") is False): print("shwoopsie")   if not (has_adjacent_repeats("Hanoverr") is True): print("error")

Refine the is_palindrome function to work with arbitrary strings, by ignoring non-letter characters and the distinction between upper- and lowercase letters. For example, if the input string is "Madam, I’m Adam!" then you’d first strip off the last character because it isn’t a letter, and recursively check whether the shorter string "Madam, I’m Adam" is a palindrome. c++

This is ML. Need help with code through SOML. And working with java (6p) Function max3 of type int int int - int that returns the largest of three integers For example max3 (3, 11, 7) should return 11.

In Kotlin, Write the function divIntSafe(a: Int, b:Int).  This function should take two Ints, convert them to doubles, divide the first by the second, and return the result. Write code that creates a list of the inverses of the Ints from 1 to 10,  Use a lambda expression as the initializer expression. Then do it again with divIntSafe function as the initializer expression.

There is a string of characters G = g1,g2,g3,...sn with no non-alphabetic characters (i.e no punctuation or spaces). You are also given a function dict(b,i,j), with an input of string b and two indices (i&j). This function will return true if bi...j is a word in the dictionary, and false if not. Please provide a simple dynamic programming solution that can determine if the string F is a sequence of valid dictionary words. State the size of the table, how the table is filled, which elements are filled in first, and where the solution is found. Please find the running time of the algorithm (assume that all calls to the function are O(1)).

Write a Python function (give it any name you choose) to analyze a text string given to it. The function will receive one single string as argument It will return two tuples of two elements each: One tuple contains the word with the maximum occurrence in the input text and the number of its occurrence. The other tuple contains the longest word with in the input text and the number of characters in it. The function should be called like function1(text), where text is a string variable. Use the paragraph below to test your code:   text = ‘’’During a wet autumnal walk, I was explaining to my girlfriend about my recent presentations. I've been doing my 'Getting Started with Python' talk at Aruba Airheads meet-ups. I recorded an early version of it, see below. One point I mentioned is that the reaction is always mixed. When I ask who is learning Python, about 5% of each audience put their hands up. Regularly people object to the idea of network engineers learning Python. The arguments…

Remains code.  Implement regular expression matching with support for '.' and '*'. '.' Matches any single character.'*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be:bool is_match(const char *s, const char *p) Some examples:is_match("aa","a") → falseis_match("aa","aa") → trueis_match("aaa","aa") → falseis_match("aa", "a*") → trueis_match("aa", ".*") → trueis_match("ab", ".*") → trueis_match("aab", "c*a*b") → true""" def is_match(str_a, str_b):    """Finds if `str_a` matches `str_b`     Keyword arguments:    str_a -- string    str_b -- string    """    len_a, len_b = len(str_a) + 1, len(str_b) + 1    matches = [[False] * len_b  for _ in range(len_a)]     # Match empty string with empty pattern    matches[0][0] = True     # Match empty string with .*    for i, element in enumerate(str_b[1:], 2):        matches[0][i] = matches[0][i - 2] and element == '*'     for i, char_a in…

Finally, we will do some simple analysis - ranking of words. Write a function word_ranking(corpus, n, sort_index) which takes input parameters corpus (type list), n (type int), and sort_index (type int) and returns a list containing tuples of words and their frequencies in the top n of words. Here, corpus is a list of sentences. n is the number of ranked words to return. The resulting list should then be sorted based on the sort_index; sort_index = should sort the list of tuples in ascending alphabetical order, while sort_index = 1 should sort the list of tuples by the frequencies in descending order. All other numeric values for sort_index should return an empty list (don't need to consider non- integer inputs). For example, we have: corpus = ['hi hi hi hi', 'hello hello say bye', 'bye bye'] n = 3 sort_index = 1 The function should return: [('hi', 4), ('bye', 3), ('hello', 2)] While sort_index = 0 should return: [('bye', 3), ('hello', 2), ('hi', 4)] You can assume n would be selected…

Finally, we will do some simple analysis – ranking of words. Write a function word_ranking(corpus, n, sort_index) which takes input parameters corpus (type list), n (type int), and sort_index (type int) and returns a list containing tuples of words and their frequencies in the top n of words. Here, corpus is a list of sentences. n is the number of ranked words to return. The resulting list should then be sorted based on the sort_index; sort_index = 0 should sort the list of tuples in ascending alphabetical order, while sort_index = 1 should sort the list of tuples by the frequencies in descending order. All other numeric values for sort_index should return an empty list (don't need to consider non-integer inputs). For example, we have: corpus = ['hi hi hi hi', 'hello hello say bye', 'bye bye']n = 3sort_index = 1   The function should return:   [('hi', 4), ('bye', 3), ('hello', 2)]   While sort_index = 0 should return:   [('bye', 3), ('hello', 2), ('hi', 4)]     You can assume n would…

Write a python function count_matches that, given two strings, counts the number of positions at which the characters are the same. For example,  count_matches('conflate', 'banana') returns 2, conflate banana     ^    ^ since the n's match at index 1 and the a's match at index 5. The strings to not need to be the same length.  The count_matches function does not read input or print output.