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Let us consider a memory that includes two instructions. First instruction is located at memory address 045 that includes an address mode bit 0, an operation code 101, an address 160. The second instruction is located at the end of a subroutine that includes an address mode bit 1, an operation code 100, an address 160. The subroutine starts at memory location 161 and the content of the PC is equal to 046. a) Draw two block diagrams of the memory to represent the status of the above instructions before and after execution phase; b) State the relationship between two instructions mentioned. Hints: You can refer to Table 1. Table 1: Basic Computer Instructions Hexadecimal code Symbol 1 = 0 I = 1 Description

Let us consider a memory that includes two instructions. First instruction is located at memory address 045 that includes an address mode bit 0, an operation code 101, an address 160. The second instruction is located at the end of a subroutine that includes an address mode bit 1, an operation code 100, an address 160. The subroutine starts at memory location 161 and the content of the PC is equal to 046. a) Draw two block diagrams of the memory to represent the status of the above instructions before and after execution phase; b) State the relationship between two instructions mentioned. Hints: You can refer to Table 1. Table 1: Basic Computer Instructions Hexadecimal code Symbol 1 = 0 I = 1 Description

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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QUESTION 3 Let us consider a memory that includes two instructions. First instruction is located at memory address 045 that includes an address mode bit 0, an operation code 101, an address 160. The second instruction is located at the end of a subroutine that includes an address mode bit 1, an operation code 100, an address 160. The subroutine starts at memory location 161 and the content of the PC is equal to 046. a) Draw two block diagrams of the memory to represent the status of the above instructions before and after execution phase; b) State the relationship between two instructions mentioned. Hints: You can refer to Table 1. Table 1: Basic Computer Instructions Hexadecimal code Symbol I = 0 I = 1 Description AND AND memory word to AC Add memory word to AC Load memory word to AC Store content of AC in memory Branch unconditionally Branch and save return address Оххх 8xxx ADD 1xxx 9xxx Axxx Вххх Cxxx Dxxx LDA 2xxx STA BUN 3xxx BSA ISZ 4xxx 5xxx бххх Exxx Increment and skip if zero Clear AC CLA CLE 7800 7400 7200 7100 7080 7040 7020 7010 Clear E Complement AC Complement E Circulate right AC and E Circulate left AC and E СМА СМЕ ČIR CIL Increment AC Skip next instruction if AC positive Skip next instruction if AC negative Skip next instruction if AC zero Skip next instruction if E is 0 Halt computer INC SPA SNA SZA 7008 7004 SZE 7002 HLT 7001 Input character to AC Output character from AC Skip on input flag Skip on output flag Interrupt on Interrupt off INP F800 OUT F400 SKI F200 SKO ION F100 F080 IOF F040
Transcribed Image Text:QUESTION 3 Let us consider a memory that includes two instructions. First instruction is located at memory address 045 that includes an address mode bit 0, an operation code 101, an address 160. The second instruction is located at the end of a subroutine that includes an address mode bit 1, an operation code 100, an address 160. The subroutine starts at memory location 161 and the content of the PC is equal to 046. a) Draw two block diagrams of the memory to represent the status of the above instructions before and after execution phase; b) State the relationship between two instructions mentioned. Hints: You can refer to Table 1. Table 1: Basic Computer Instructions Hexadecimal code Symbol I = 0 I = 1 Description AND AND memory word to AC Add memory word to AC Load memory word to AC Store content of AC in memory Branch unconditionally Branch and save return address Оххх 8xxx ADD 1xxx 9xxx Axxx Вххх Cxxx Dxxx LDA 2xxx STA BUN 3xxx BSA ISZ 4xxx 5xxx бххх Exxx Increment and skip if zero Clear AC CLA CLE 7800 7400 7200 7100 7080 7040 7020 7010 Clear E Complement AC Complement E Circulate right AC and E Circulate left AC and E СМА СМЕ ČIR CIL Increment AC Skip next instruction if AC positive Skip next instruction if AC negative Skip next instruction if AC zero Skip next instruction if E is 0 Halt computer INC SPA SNA SZA 7008 7004 SZE 7002 HLT 7001 Input character to AC Output character from AC Skip on input flag Skip on output flag Interrupt on Interrupt off INP F800 OUT F400 SKI F200 SKO ION F100 F080 IOF F040
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