A computer employs RAM chips of 128 x 8 and ROM chips of 512 x 8. The computer system needs 256 bytes of RAM, 1024 x 16 of ROM, and two interface units with 256 registers each. A memory mapped I/O configuration is used. The two higher -order bits of the address bus are assigned 00 for RAM, 01 for ROM, and 10 for interface registers. a. Compute total number of decoders are needed for the above system?
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- a. We are given a system with 2 levels of cache, L1 and L2. The CPU directly interfaces to the L1 cache, which has a hit time of 1 ns and a hit rate of 0.4. On misses, the L1 accesses the L2 cache, which has an access time of 20 ns, and a hit rate of 0.8. If the L2 misses, it accesses the main memory, which has an access time of 100 ns. Determine the average memory access time, of the CPU to the memory hierarchy.b. A cache is inserted between the main memory, which is 32 MB, and the CPU. This cache can accomodate 64 blocks and each block can accomodate 128 words (2B per word). How many possible blocks can be stored in one cache block if it is a direct-mapped cache?Let's pretend for a moment that we have a byte-addressable computer with 16-bit main memory addresses and 32-bit cache memory blocks, and that it employs two-way set associative mapping. Knowing that each block has eight bytes, please calculate the size of the offset field and provide evidence of your calculations.Suppose that a computer has a processor with two L1 caches, one for instructions and one for data, and an L2 cache. Let τ be the access time for the two L1 caches. Themiss penalties are approximately 15τ for transferring a block from L2 to L1, and 100τ fortransferring a block from the main memory to L2. For the purpose of this problem, assumethat the hit rates are the same for instructions and data and that the hit rates in the L1 andL2 caches are 0.96 and 0.80, respectively.(a) What fraction of accesses miss in both the L1 and L2 caches, thus requiring accessto the main memory?(b) What is the average access time as seen by the processor?(c) Consider the following change to the memory hierarchy. The L2 cache is removedand the size of the L1 caches is increased so that their miss rate is cut in half. Whatis the average memory access time as seen by the processor in this case
- In this problem, you will explore processor frequency in the context of the speed of light.Suppose you have overclocked a processor to 8,722.78MHz. This processor can execute one instruction per cycle. Further let us suppose that the system is accessing a magnetic disk (HD) with an access time of 11ms. 1. Suppose that you are designing the machine architecture and want to guarantee the CPU can obtain data from memory within 4 CPU cycles. Given that the address has to travel from the CPU to the memory unit (MMU) and that the data has to travel from memory to the CPU, what is the maximum distance between CPU and the MMU if the signal on the memory bus propagates at 75% of the speed of light?Let's pretend for a moment that we have a byte-addressable computer with fully associative mapping, 16-bit main memory addresses, and 32 blocks of cache memory. The following holds true if each block is 16 bits in size:a) Determine how many bytes the offset field is.Measure the tag field's width and height in pixels (b).A 32-bit computer has a memory of 256 KB and a cache line size of 64 bytes. The memory cache access time is 5ns. This cache is 4-way associative and use LRU as a replacement algorithm. a) What is the number of lines and sets of this memory cache? b) What is the block size transferred between the cache memory and the main memory? c) If the time to transfer a line to cache memory is 200 ns, what is the hit ratio needed to obtain an average access time of 20 ns?
- hi can u anwser this qustion plesc ? Consider a Computer which has a memory which is capable of storing 4096 K words and each word in memory can be of size 32 bits. The computer supports a total of “K” addressing modes, and it has “M” computer registers. The computer supports instructions, where each instruction consists of following fields: Mode Operation code Register Register Memory AddressGiven that each instruction will be stored in one memory word, discuss with a suitable diagram the format of instruction by specifying number of bits for each field of instruction. Discuss each field of instruction.Note: Choose your own values for K (number of addressing modes) and M (number of Registers) k=8 m=50Assume that a personal computer must get FIVE pieces of data from itsmemory for every operation (one piece of data indicates Which instructionto perform: the other is the intormation which is operated on). If thecomputer is the size of a typical PC. how long does it take to get these pieceof data? From this, what is the maximum rate at which the PC can executeuctions?A certain microprocessor requires either 2, 3, 4, 8, or 12 machine cycles to perform various operations. A total of 25% of its instructions require 2 machine cycles, 20% require 3 machine cycles, 17.5% require 4 machine cycles, 12.5% require 8 machine cycles, and 25% require 12 machine cycles.Q) Suppose this system requires an extra 20 machine cycles to retrieve an operand from memory. It has to go to memory 40% of the time. What is the average number of machine cycles per instruction for this microprocessor, including its memory fetch instructions?
- A certain processor uses separate instruction and data caches with hit ratios 97% and 94% respectively. The access time from the processor to either cache is 1 clock cycle, and the block transfer time between the caches and main memory is 67 clock cycles. Among blocks replaced in the data cache, 21% is the percentage of dirty blocks (Dirty means that the cache copy is different from the memory copy). Assuming a write-back policy, what is the AMAT for the instructions in this system? Round to 2 decimal places.Consider a memory system with a cache access time of 100ns and a memory access timeof 1200ns. If the effective access time is 10% greater than the cache access time, what is thehit ratio H?Q2) Given a physical memory of 8 k and a cache memory of 512 bytes with block size 64 bytes. The system uses associative mapping with set size 2 lines per setA- How the memory address will be split to indicate tag, and offset B- What is the size of tag directory.