n python define a function called indexCh. It will take string from user and removes the nth index character from the non-empty string.

here is a and b part plz solve c part   #include <iostream>#include <string.h>#include <stdlib.h>#include <sstream>#include <cmath>using namespace std; int main(){   /*Variable declarations*/int higestDegree,higestDegree1;int diffDegree,smallDegree;std::stringstream polynomial,addpolynomial;/*prompt for degree*/std::cout<<"Please enter higest degree of polynomial"<<std::endl;std::cin>>higestDegree; std::cout<<"Please Enter highest degree of 2nd polynomial"<<std::endl;std::cin>>higestDegree1;int *cofficient=new int[higestDegree+1];//cofficient array creation for 1st polynomailint *cofficient1=new int[higestDegree1+1];//cofficient array creation for 2st polynomail /*taking cofficient for 1st polynomial*/std::cout<<"Please enter cofficient of each term from higest degree to lowest for 1st polynomial"<<std::endl;for(int i=0;i<=higestDegree;i++){std::cin>>cofficient[i];}/*taking cofficient for 2st…

JS Write a function named number_of_pairs whose parameter is an object/dictionary with strings as keys and integers as values. Your function should returns the number of key-value pairs in the parameter.

JS Write a function named list_concat that has a single parameter. This parameter will be a list/array. The parameter's entries will be strings. Your function needs to return a string. The returned string's value should be the concatention of all of the entries in the parameter with a space after each entry. Sample test cases: list_concat(["single"]) evaluates to "single list_concat(["limit", "break", "ready"]) evaluates to "limit break ready

python exercise: Write a Python function called get_top_students that takes the list of dictionaries as input and returns a dictionary containing the name and GPA of the top two students in the list. Each dictionary has the following keys: "name", "age", "major", and "gpa".

Please complete the following functions:  1. int loadDictionary(istream& dictfile, vector<string>& dict)  2. int permute(string word, vector<string>& dict, vector<string>& results) 3. void display(vector<string>& results)

String orig_string is read from input. Assign variable sliced_string with the orig_string slice that excludes the characters at indices 10 and 11.

Edef reverse_sentence (s: str) -> str: Given a sentence , we define a word within to be a continuous sequence of characters in that starts with a capital letter and ends before the next capital letter in the string or at the end of the string, whichever comes first. A word can include a mixture of punctuation and spaces. This means that in the string 'ATest string!', there are in fact only two words: 'A' and 'Test string!'. Again, keep in mind that words start with a capital letter and continue until the next capital letter or the end of the string, which is why we consider 'Test string!' as one word. This function will reverse each word found in the string, and return a new string with the reversed words, as illustrated in the doctest below. >>> reverse_sentence('ATest string!') 'A!gnirts tseT' return

Write a function calculate_expression(values) that calculates and returns the value of the following expression: ((angle - 34) ** (1./a)) / (vol ** b) The function receives as input a dictionary containing the values of the parameters (a, b, vol, angle). The string name of the parameter is the key and the associated number is the value. The result must be rounded to three digits after the comma.

PYTHON Complete the function below, which takes two arguments: data: a list of tweets search_words: a list of search phrases The function should, for each tweet in data, check whether that tweet uses any of the words in the list search_words. If it does, we keep the tweet. If it does not, we ignore the tweet. data = ['ZOOM earnings for Q1 are up 5%', 'Subscriptions at ZOOM have risen to all-time highs, boosting sales', "Got a new Mazda, ZOOM ZOOM Y'ALL!", 'I hate getting up at 8am FOR A STUPID ZOOM MEETING', 'ZOOM execs hint at a decline in earnings following a capital expansion program'] Hint: Consider the example_function below. It takes a list of numbers in numbers and keeps only those that appear in search_numbers. def example_function(numbers, search_numbers): keep = [] for number in numbers: if number in search_numbers(): keep.append(number) return keep   def search_words(data, search_words):