numbers = [2, 4, 5, 8] user_input = input () while user_input != 'end': try: #Possible ValueError diviforint (user_input) if divisor > 20: # Possible NameError # compute() is not defined result = compute (result) elif divisor < 0: #Possible IndexError result = numbers [divisor] else: #Possible ZeroDivisionError result = 20 // divisor print (result, end-' ') except (ValueError, ZeroDivisionError): print ('r', end=' ') except (NameError, IndexError): print ('s', end=' ') user_input = input () print ('OK') # // truncates to an integer Input nine -10 0 2 -2 95 end Output

SYNTAX ERROR HELP - PYTHON This also happens for several other 'return result' lines in the code.   import randomdef rollDice():    num1 = random.randint(1, 6)    num2 = random.randint(1, 6)    return num1, num2def determine_win_or_lose(num1, num2):    result = -1    total = num1 + num2print(f"You rolled {num1} + {num2} = {total}")if total == 2 or total == 3 or total == 12:    result = 0elif total == 7 or total == 11:    result = 1else:    print(f"point is {total}")    x = determinePointValueResult(total)if x == 1:    result = 1else:    result = 0    return resultdef determinePointValueResult(pointValue):    total = 0    result = -1while total != 7 and total != pointValue:    num1, num2 = rollDice()    total = num1 + num2if total == pointValue:    result = 1elif total == 7:    result = 0print(f"You rolled {num1} + {num2} = {total}")return resultwhile i < n:    num1, num2 = rollDice()    result = determine_win_or_lose(num1, num2)if result == 1:    winCounter += 1    print("You…

//main.cpp #include "Person.h"#include "Seller.h"#include "Powerseller.h"#include <iostream>#include <list>#include <fstream>#include <string> using namespace std; void printMenu();void printSellers(list<Seller*> sellers);void checkSeller(list<Seller*> sellers);void addSeller(list<Seller*> sellers);void deleteSeller(list<Seller*> &sellers); int main() {  list<Seller*> sellers;  ifstream infile;  infile.open("sellers.dat");  if (!infile) {      cerr << "File could not be opened." << endl;      exit(1);  }  char type;  while (!infile.eof())   {      infile >> type;      if (type == 'S')       {        Seller* newseller = new Seller;        newseller -> read(infile);        sellers.push_back(newseller);      }               if (type == 'P')       {        Powerseller* newpowerseller = new Powerseller;        newpowerseller -> read(infile);        sellers.push_back(newpowerseller);      }  }  infile.close();…

Module main() // Local variables Constant Integer SIZE = 18 Declare Integer numbers[SIZE] = 5658845, 4520125, 7895122, 8777541,       8451277, 1302850, 8080152, 4562555, 5552012, 5050552, 7825877, 1250255, 1005231, 6545231, 3852085, 7576651, 7881200, 4581002       Declare Integer inputNumber, found = 0   // Get number Display “Enter number to validate: “ Input inputNumber   // Validate number For index = 0 to SIZE – 1 If inputNumber == numbers[index] Then       Set found = 1       Set index = SIZE End If       End For   // Show if valid If found == 1 Then Display “Number is valid.” Else Display “Number is not valid.” End If   End Module Flowchart please

In Python, grades_dict = {'Wally': [87,96,70], 'Eva': [100,87,90], 'Sam': [94,77,90], 'Katie': [100,81,82],                'Bob': [83, 65, 85]} Ask user to enter the names of the rows, i.e., indices. You can use: len(grades) to get the number of rows of the DataFrame. In addition, using the sort_index() method, ask user whether they wish to sort by rows or by columns and whether to sort in ascending or descending order (do not use any if-else statements)

def is_balanced(root):    return __is_balanced_recursive(root) def __is_balanced_recursive(root):    """    O(N) solution    """    return -1 != __get_depth(root) def __get_depth(root):    """    return 0 if unbalanced else depth + 1    """    if root is None:        return 0    left = __get_depth(root.left)    right = __get_depth(root.right)    if abs(left-right) > 1 or -1 in [left, right]:        return -1    return 1 + max(left, right) # def is_balanced(root):#     """#     O(N^2) solution#     """#     left = max_height(root.left)#     right = max_height(root.right)#     return abs(left-right) <= 1 and is_balanced(root.left) and#     is_balanced(root.right) # def max_height(root):#     if root is None:.

Non dynamic.arrays are allocated at runtime where dynamic arrays are allocated at compile time. True False Question 4 There are other ways to end a loop other than just the loop condition evaluating to false. True False

Computer Science Part C: Interactive Driver Program Write an interactive driver program that creates a Course object (you can decide the name and roster/waitlist sizes). Then, use a loop to interactively allow the user to add students, drop students, or view the course. Display the result (success/failure) of each add/drop.

struct Info { int id; float cost; }; Given the struct above, the following code segment will correctly declare and initialize an instance of that struct. Info myInfo = {10,4.99}; Group of answer choices True False   ==============   Consider the following code fragment. int a[] = {3, -5, 7, 12, 9}; int *ptr = a; *ptr = (*ptr) + 1; cout << *ptr; Group of answer choices 4 -5 3 Address of -5   =============== What will happen if I use new without delete? Group of answer choices The program will never compile The program will never run The program will run fine without memory leak None of these

Trace through the following program and show the output. Show your work for partial credit. public class Employee { private static int empID = 1111l; private String name , position; double salary; public Employee(String name) { empID ++; this.name 3 пате; } public Employee(Employee obj) { empID = obj.empĪD; пате %3D оbj.naте; position = obj.position; %3D public void empPosition(String empPosition) {position = empPosition;} public void empSalary(double empSalary) { salary = empSalary;} public String toString() { return name + " "+empID + " "+ position +" $"+salary; public void setName(String empName){ name = empName;} public static void main(String args[]) { Employee empOne = new Employee("James Smith"), empTwo; %3D empOne.empPosition("Senior Software Engineer"); етрOпе.етpSalary(1000); System.out.println(empOne); еmpTwo empTwo.empPosition("CEO"); System.out.println(empOne); System.out.println(empTwo); %3D етpОпе empOne ;