Overview of problem: A boy pushes a toy block up an incline and releases it at the very top. He thinks the block willland in his room, but his sister believes he is trying to launch it across the hallway into her room. Mom is not going to be10-19happy if she steps on the block when she walks down the hall. Assume that the top end of the incline is 1.00 m (horizontally)from the boy's door and that the hallway is 1.00 m wide. Who is right?Note that as a whole, this problem does not match any single type of problem that you have learned; however, you candivide it into three separate problems. The following will guide you through the steps. Only one Evaluation is necessary.(a) A boy pushes a 0.750 kg wooden block up an incline such that the force is parallel (not horizontal, which is moredifficult) with the incline and has a magnitude of 8.43 N. The incline is at anand the coefficient of kinetic friction between the block and incline is 0.178. Determine the acceleration of theangle of 28.0° and is 0.463 m long,block.(b) Start on a new sheet of paper.You will need a newSimplify. Assuming that the block starts from rest and that thelong, what is the velocity of the block when it arrives at the top of the incline? You can checkincline is 0.463 myour work by calculating the elapsed time to show it equals 0.426 s.(c) Start ona new sheet of paper. You will need a newSimplify.Just as the block reaches the top of the incline, theboy releases it such that it is launched at the speed found in the previous part. What type of motion is occurringnow? You will need the angle of the incline to determine the velocity components and the height of the blockwhen it is launched. (The height is found using either the sine or cosine function - which one?) Which room doesthe block landyou must demonstrate this quantitatively. What is the speed of the block when it hits the floor?What angle does the final velocity make with respect to the horizontal? (Answers for the last two questions:3.00 m/s and 50.2°.)BthE-FECn

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Asked Oct 9, 2019
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Overview of problem: A boy pushes a toy block up an incline and releases it at the very top. He thinks the block will
land in his room, but his sister believes he is trying to launch it across the hallway into her room. Mom is not going to be
10-19
happy if she steps on the block when she walks down the hall. Assume that the top end of the incline is 1.00 m (horizontally)
from the boy's door and that the hallway is 1.00 m wide. Who is right?
Note that as a whole, this problem does not match any single type of problem that you have learned; however, you can
divide it into three separate problems. The following will guide you through the steps. Only one Evaluation is necessary.
(a) A boy pushes a 0.750 kg wooden block up an incline such that the force is parallel (not horizontal, which is more
difficult) with the incline and has a magnitude of 8.43 N. The incline is at an
and the coefficient of kinetic friction between the block and incline is 0.178. Determine the acceleration of the
angle of 28.0° and is 0.463 m long,
block.
(b) Start on a new sheet of paper.
You will need a new
Simplify. Assuming that the block starts from rest and that the
long, what is the velocity of the block when it arrives at the top of the incline? You can check
incline is 0.463 m
your work by calculating the elapsed time to show it equals 0.426 s.
(c) Start ona new sheet of paper. You will need a new
Simplify.
Just as the block reaches the top of the incline, the
boy releases it such that it is launched at the speed found in the previous part. What type of motion is occurring
now? You will need the angle of the incline to determine the velocity components and the height of the block
when it is launched. (The height is found using either the sine or cosine function - which one?) Which room does
the block land
you must demonstrate this quantitatively. What is the speed of the block when it hits the floor?
What angle does the final velocity make with respect to the horizontal? (Answers for the last two questions:
3.00 m/s and 50.2°.)
BthE
-FECn
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Overview of problem: A boy pushes a toy block up an incline and releases it at the very top. He thinks the block will land in his room, but his sister believes he is trying to launch it across the hallway into her room. Mom is not going to be 10-19 happy if she steps on the block when she walks down the hall. Assume that the top end of the incline is 1.00 m (horizontally) from the boy's door and that the hallway is 1.00 m wide. Who is right? Note that as a whole, this problem does not match any single type of problem that you have learned; however, you can divide it into three separate problems. The following will guide you through the steps. Only one Evaluation is necessary. (a) A boy pushes a 0.750 kg wooden block up an incline such that the force is parallel (not horizontal, which is more difficult) with the incline and has a magnitude of 8.43 N. The incline is at an and the coefficient of kinetic friction between the block and incline is 0.178. Determine the acceleration of the angle of 28.0° and is 0.463 m long, block. (b) Start on a new sheet of paper. You will need a new Simplify. Assuming that the block starts from rest and that the long, what is the velocity of the block when it arrives at the top of the incline? You can check incline is 0.463 m your work by calculating the elapsed time to show it equals 0.426 s. (c) Start ona new sheet of paper. You will need a new Simplify. Just as the block reaches the top of the incline, the boy releases it such that it is launched at the speed found in the previous part. What type of motion is occurring now? You will need the angle of the incline to determine the velocity components and the height of the block when it is launched. (The height is found using either the sine or cosine function - which one?) Which room does the block land you must demonstrate this quantitatively. What is the speed of the block when it hits the floor? What angle does the final velocity make with respect to the horizontal? (Answers for the last two questions: 3.00 m/s and 50.2°.) BthE -FECn

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Expert Answer

Step 1

Write the expression for net force along the incline

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ma = F -mg cos-mgsin F-mg cos-mg sin e (8.43 N)-(0.178) (0.750 kg) (9.8 m/s) cos (28.0°) - (0.750 kg ) (9.8 m/s )sin (28.0°) (0.750kg) -5.10 m/s

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Step 2

 (b)

Write the kinematic expression for final velocity

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v= \u? +2as oj2(5.10 m/s(.463m) =2.17 m/s

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Step 3

Write the expression f...

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V-u t= a (2.17 m/s)-(0) (5.10 m/s =0.426 s

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