Oxidation: Reducing agent Sb*10-2 + H2O –→ Sb*³Oz^² + 2H + _ Reduction: Oxidizing agent 1;0 + _ • → 21-1 * Number of e- gain/loss for 1 mole of antimony is

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Experiment 4. Assay of Antimony Potassium Tartrate
Principle:
lodimetry
The percentage purity of antimony potassium tartrate set by the USP is 99 to 103%
Procedure (reduce formulation to %)
1. Dissolve 500 mg of Antimony Potassium Tartrate (CaH.K,Sb;O12" 3H;0) in 30 ml of water
2. Add 25 ml of cold saturated of sodium bicarbonate solution and a few drops of starch TS
3. Immediately titrate with 0.1 N iodine to the production of a persistent blue color, where
theoretical volume consumed for each trial is provided in the table below).
7. Calculate the percentage purity of the sample, using the formula:
ml were consumed (the
Nx ml x meg
% =
x 100 %
We
Reaction (fill in the coefficients on the blank spaces):
1 mole of CaHaK2Sb2O12 3H2O is equal to 2 moles of KOOCCHOHCHOHCOO(SbO)
коосснонснонсоO(SbO) + l2 + HаО — коосснонснонсоO(SbOг) + 2HI
Oxidation: Reducing agent
Sb*10-2 + H2O → Sb*3O22 + 2H +_ e-
Reduction: Oxidizing agent
120 +_ e- - 21-1
* Number of e- gain/loss for 1 mole of antimony is :
since 2 moles will be consumed, ••x_ moles), the factor of antimony potassium tartrate will be
Data and Results:
Trial 1
Trial 2
Trial 3
Weight of potassium antimony tartrate
Volume of iodine solution
15.0 ml
15.2 ml
15.5 ml
Percentage purity
Average percentage purity
Calculation and Conclusion
On space below, solve the titer value and average percentage purity of the sample then interpret.
Transcribed Image Text:Experiment 4. Assay of Antimony Potassium Tartrate Principle: lodimetry The percentage purity of antimony potassium tartrate set by the USP is 99 to 103% Procedure (reduce formulation to %) 1. Dissolve 500 mg of Antimony Potassium Tartrate (CaH.K,Sb;O12" 3H;0) in 30 ml of water 2. Add 25 ml of cold saturated of sodium bicarbonate solution and a few drops of starch TS 3. Immediately titrate with 0.1 N iodine to the production of a persistent blue color, where theoretical volume consumed for each trial is provided in the table below). 7. Calculate the percentage purity of the sample, using the formula: ml were consumed (the Nx ml x meg % = x 100 % We Reaction (fill in the coefficients on the blank spaces): 1 mole of CaHaK2Sb2O12 3H2O is equal to 2 moles of KOOCCHOHCHOHCOO(SbO) коосснонснонсоO(SbO) + l2 + HаО — коосснонснонсоO(SbOг) + 2HI Oxidation: Reducing agent Sb*10-2 + H2O → Sb*3O22 + 2H +_ e- Reduction: Oxidizing agent 120 +_ e- - 21-1 * Number of e- gain/loss for 1 mole of antimony is : since 2 moles will be consumed, ••x_ moles), the factor of antimony potassium tartrate will be Data and Results: Trial 1 Trial 2 Trial 3 Weight of potassium antimony tartrate Volume of iodine solution 15.0 ml 15.2 ml 15.5 ml Percentage purity Average percentage purity Calculation and Conclusion On space below, solve the titer value and average percentage purity of the sample then interpret.
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