Part A How many moles of PCI5 will be produced if .331 moles of P4 is reacted with an excess of Cl2 using the following equation. P4(s) + 10 Cl2(g) → 4 PCI5(g) 1.655 mol 662 mol .331 mol 1.324 mol .993 mol Submit Request Answer Provide Feedback Type here to search

Part A How many moles of PCI5 will be produced if .331 moles of P4 is reacted with an excess of Cl2 using the following equation. P4(s) + 10 Cl2(g) → 4 PCI5(g) 1.655 mol 662 mol .331 mol 1.324 mol .993 mol Submit Request Answer Provide Feedback Type here to search

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter13: Spontaneous Processes And Thermodynamic Equilibrium

Section: Chapter Questions

Problem 48AP

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

How many moles of PCl₅ will be produced if .331 moles of P₄ is reacted with an excess of Cl₂ using the following equation?

P₄(s)+10Cl₂(g) > 4PCI₅(g)

Part A
How many moles of PCI5 will be produced if .331 moles of P4 is reacted with an excess of Cl2 using the following equation.
P4(s) + 10 Cl2(g) → 4 PCI5(g)
1.655 mol
662 mol
.331 mol
1.324 mol
.993 mol
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